Programming Questions

Q:

public abstract interface Frobnicate { public void twiddle(String s); } 

Which is a correct class?

A) public abstract class Frob implements Frobnicate { public abstract void twiddle(String s) { } } B) public abstract class Frob implements Frobnicate { }
C) public class Frob extends Frobnicate { public void twiddle(Integer i) { } } D) public class Frob implements Frobnicate { public void twiddle(Integer i) { } }
 
Answer & Explanation Answer: B) public abstract class Frob implements Frobnicate { }

Explanation:

B is correct, an abstract class need not implement any or all of an interface’s methods

Report Error

View Answer Report Error Discuss

Filed Under: Programming

6 61097
Q:

How many times i value is checked in the below code?

       #include <stdio.h>
        int main()
        {
            int i = 0;
            do {
                i++;
                printf( "In while loopn" );
            } while (i < 3);
        }

A) 2 B) 3
C) 4 D) 1
 
Answer & Explanation Answer: B) 3

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Programming

8 47429
Q:

What will be output when you will execute following c code?

#include <stdio.h>
void main()

{
    int const SIZE = 5;
    int expr;
    double value[SIZE] = { 2.0, 4.0, 6.0, 8.0, 10.0 };
    expr=1|2|3|4;
    printf ( "%f", value[expr] );
}

A) 2.000000 B) 4.000000
C) 8.000000 D) Compilation error
 
Answer & Explanation Answer: D) Compilation error

Explanation:

Size of any array in c cannot be constantan variable.

Report Error

View Answer Report Error Discuss

Filed Under: Programming

7 47369
Q:

What will be output of following c code?

#include <stdio.h>
int main()

{
    int x=123;
    int i={
         printf("c" "++")
    };
    for(x=0;x<=i;x++){
         printf("%x ",x);
    }
    return 0;

}

Answer

Output: c++0 1 2 3

Explanation: First printf function will print: c++ and return 3 to variable i.For loop will execute three time and printf function will print 0, 1, 2 respectively.

Report Error

View answer Workspace Report Error Discuss

Subject: Programming

71 45631
Q:

main()

{

char *p; p = "Hello";

printf ("%cn", *&*p);

}

A) H B) Hello
C) Compilation error D) H E L L O
 
Answer & Explanation Answer: A) H

Explanation:

* is a dereference operator & is a reference operator. They can be applied any number of times provided it is meaningful. Here p points to the first character in the string "Hello". *p dereferences it and so its value is H. Again & references it to an address and * dereferences it to the value H

Report Error

View Answer Report Error Discuss

Filed Under: Programming
Job Role: Software Architect

26 45011
Q:

main()

{

char s[ ] = "man";

int i;

for( i=0; s[ i ]; i++)

printf( "n%c%c%c%c", s[ i ], *(s+i), *(i+s), i[s] );

}

A) mmmm aaaa nnnn B) aaaa mmmm nnnn
C) nnnn aaaa mmmm D) None
 
Answer & Explanation Answer: A) mmmm aaaa nnnn

Explanation:

s[i], *(i+s), *(s+i), i[s] are all different ways of expressing the same idea.Generally array name is the base address for that array. Here s is the base address. i is the index number/displacement from the base address. So, indirecting it with * is same as s[i]. i[s] may be surprising. But in the case of C it is same as s[i].

Report Error

View Answer Report Error Discuss

Filed Under: Programming

28 34224
Q:

#define clrscr() 100

main()

{

clrscr();

printf( "%dn", clrscr() );

}

A) 100 B) 0
C) Compilation error D) Exception occurs
 
Answer & Explanation Answer: A) 100

Explanation:

Preprocessor executes as a seperate pass before the execution of the compiler. So textual replacement of clrscr() to 100 occurs.The input program to compiler looks like this :

main ()

{

100;

printf("%d\n",100);

}

Note: 100; is an executable statement but with no action. So it doesn't give any problem.

Report Error

View Answer Report Error Discuss

Filed Under: Programming

14 28316
Q:

What will be output of following program?


#include <stdio.h>
int main()

{
   void (*p)();
   int (*q)();
   int (*r)();
   p = clrscr;
   q = getch;
   r = puts;
  (*p)();
  (*r)("www.sawaal.com");
  (*q)();
  return 0;
}

A) NULL B) www.sawaal.com
C) Compilation error D) None of above
 
Answer & Explanation Answer: B) www.sawaal.com

Explanation:

p is pointer to function whose parameter is void and return type is also void. r and q is pointer to function whose parameter is void and return type is int . So they can hold the address of such function.

Report Error

View Answer Report Error Discuss

Filed Under: Programming

3 27159