Puzzles Questions

13 x 2 = 26 => Z (opposite side)

12 x 2 = 24 => X (opposite side)

13 x 1 = 13 => M (opposite side)

12 x 1 = 12 => L (opposite side)

Since, in one hour, two hands of a clock coincide only once, so, there will be value.
Required time T = 211H×30 + Ao minutes past H.
Here H - initial position of hour hand = 2 (since 2 O'clock)
A° = Required angle = 0° (Since it coincides)

T = 2112×30 + 0o minutes past 2 

=> 11011 minutes past 2

When the letters are arranged in the alphabetical order, two remains the same.

Man's Father is Madhu's Father's Son => Madhu itself. So the Man in the photograph is Madhu's son. 

Here in the above given question, the mistake is "the is reapeated twice" before mistake.

A tennis ball or badminton shuttle in which we can serve a ball or kock but we cannot eat it.

At 9 o’clock, the hour hand is at 9 and the minutes hand is at 12, i.e., the two hands are 15 min. spaces apart.
So, the minute hand should gain = (30 - 15) minutes = 15 minutes
55 minutes will be gained in 60 min.
15 minutes spaces will be gained in ((60/55) x 15) min. = 180/11 min.
The hands will be in the same straight line but not together i.e.,in 180 degrees at 180/11 min. past 9.

Since at 4 : 20 the minute hand will be at 4 and the angle between them will be same as the distance covered in degree by the hour hand in 20 minutes.

Required angle = distance of hour hand = speed × time = 12× 20 =10 degrees.