Project Manager Questions

The computer that process both analog and digital is called Hybrid computer.

The code segments B and D will compile without any error. A is not a valid way to construct a StringBuffer, you need to create a StringBuffer object using "new". B is a valid construction of a Boolean (any string other than "true" or "false" to the Boolean constructor will result in a Boolean with a value of "false"). C will fail to compile because the valid range for a byte is -128 to +127 (i.e., 8 bits, signed). D is correct, 0x1234 is the hexadecimal representation in java. E fails to compile because the compiler interprets 1.2 as a double being assigned to a float (down-casting), which is not valid. You either need an explicit cast, as in "(float)1.2" or "1.2f", to indicate a float.

ITIL (Information Technology Infrastructure Library) is owned by Axelos since, 2013.

In computing, the expansion card or board or accessory card is a printed circuit board that can be inserted into an electrical connector or expansion slot, on a computer motherboard, to add functionality to a computer system via the expansion bus.

 It can be possible in only B.C. i.e, Before Christ. That was about 2000 years ago.

 Given, 

 In 1990 B.C = 2000 + 1990 = 3990 years ago, a person is 15 years Old  

=> In 1995 B.C = 2000 + 1995 = 3995 years ago, the same person will be 10 years Old 

Therefore, In 2000 B.C = 2000 + 2000 = 4000 years ago, the same person will be 5 years Old.

The smallest unit of data storage in a computer is called Bit (Binary Digit). Half a byte (four bits) is called a Nibble.

1 bit (binary digit) = the value of 0 or 1

8 bits = 1 byte

1024 bytes = 1 kilobyte

1024 kilobytes = 1 megabyte

1024 megabytes = 1 gigabyte

1024 gigabytes = 1 terabyte

1024 terabytes = 1 petabyte

Hence, Computer storage units smallest to largest i.e, in ascending order is

 1 bit  <  1 byte  <  1 KB  <  1 MB  <  1 GB  <  1TB  <  1 PB.

Let the total capacity of tank be 90 liters.
Capacity of tank filled in 1 minute by K = 3 liters.
Capacity of tank filled in 1 minute by L = 15 liters.
Therefore, capacity of the tank filled by both K and L in 1 minute = 18 liters.
Hence, time taken by both the pipes to overflow the tank = 90/18 = 5 minutes.