Bank PO Questions

Hubs are specified or operate at Layer1 i.e, the physical layer in the OSI model. Hubs regenerate electrical signals. A hub sends data packets (frames) to all devices on a network, regardless of any MAC addresses contained in the data packet.

To enhance user experience when searching for fashion content, Google on Thursday introduced a new feature called “style ideas” in Image Search on mobile web and in Google app for Android. “Style ideas” throws up high-quality images that show how someone will look while wearing or carrying the item you searched for.

Capital expenditures are capitalized because of the timing of their estimated benefits – the lemonade stand will benefit the firm for many years. The employees’ work, on the other hand, benefits the period in which the wages are generated only and should be expensed then. This is what differentiates an asset from an expense.

The endomembrane system is composed of the different membranes that are suspended in the cytoplasm within a eukaryotic cell. These membranes divide the cell into functional and structural compartments or organelles. In eukaryotes, the organelles of the endomembrane system include the nuclear membrane, the endoplasmic reticulum, the Golgi apparatus, lysosomes, vesicles, endosomes and the cell membrane, among others.

5/8 is Nothing but to divide 5 into 8 parts.

As 5 is smaller than 8, the quotient starts with a decimal point to make 5 as 50 to be divisible by 8. (0.)

Now 50 goes for 6 times in 8 leaving a remainder 2. (0.6)

Again 2 is smaller than 8, As it already has decimal point in the quotient, now 2 becomes 20.

Now 20 goes for 2 times in 8 leaving a remainder 4. (0.62)

Again 4 is smaller than 8, As it already has decimal point in the quotient, now 4 becomes 40.

Now 40 goes for 5 times in 8 leaving a remainder 0. (0.625)

Therefore, the decimal value of 58 is 0.625.

Now find a decimal value of 1117 and Discuss your at Discuss.

The HF band is based on frequencies 3 to 30 Mhz. AM radio stations are in the HF band but normally are stated in kilohertz.

From solving 1 and 2 we get,

1.

5a(a-3)-3(a-3) = 0

(5a-3)(a-3) = 0

a = 3 or 3/5

2. 

3b(b+2)-1(b+2) = 0

b = -2 or b = 1/3

Here when a = 3, a > b for b = -2 and b = 1/3

when a = 3/5. a > b for b = -2 and b = 1/3.

Hence, it is clear that a > b.