Bank PO Questions

55min spaces are covered in 60min

60 min. spaces are covered in (60/55 x 60) min= 65+5/11 min.

loss in 64min=(65+5/11)- 64 =16/11

Loss in 24 hrs (16/11 x 1/64 x 24 x 60) min= 32 8/11.

All locks are bangles + All bangles are cars = A + A = A
= All locks are cars => Some cars are locks.
Hence conclusion (a) follows.
All keys are locks + All locks are bangles = A + A = A
= All keys are bangles => some bangles are keys.
Hence conclusion (b) follows.
All keys are bangles + All bangles are cars = A + A = A
= All keys are cars => Some cars are keys.
Hence conclusion (C) follows.

Thus all a, b and c follows.

Speed in downstream = (14 + 4) km/hr = 18 km/hr;

Speed in upstream = (14 – 4) km/hr = 10 km/hr.

Let the distance between A and B be x km. Then,

x/18 + (x/2)/10 = 19 ⇔ x/18 + x/20 = 19 ⇒ x = 180 km.

The given number series is 8, 14, 24, 40, ? .

It follows a pattern that,

8

8 x 1.5 + 2 = 14

14 x 1.5 + 3 = 24

24 x 1.5 + 4 = 40

40 x 1.5 + 5 = 65

Hence, the next number in the given number series is 65.

The given number series follows a pattern that,

$$\begin{gathered} 19 + 12 = 20 (not 21) \\ 20 + 22 = 24 \\ 24 + 32 = 33 \\ 33 + 42 = 49 \\ 49 + 52 = 74 \end{gathered}$$

Hence, the odd number in the given number series is 21.

Let the present age of the man be 'P' and son be 'Q',
Given, P + Q = 64 or Q = (64 - P)
Now the man says "I am five times as old as you were, when I was as old as you are",
So, P = 5[B - (P - Q)]
We get 6P = 10Q,
Substitute value for Q,
6P = 10(64 - P),
Therefore P = 40, Q = 24.

clearly the cow will graze a circular field of area 9856 sq m and radius equal to the length of the rope.

Let the length of the rope be r mts 

then, πr2=9856 ⇒ r2=9856×722=3136 ⇒r =56m

Here the given series 222, 271, 308, 332, 348, 357 follows a pattern that

222

222 + 49  271

271 + 36 = 307 (NOT 308)

307 + 25 = 332

332 + 16 = 348

348 + 9 = 357

Hence, the odd man in the fiven number series is 308.