Bank PO Questions and Answers with Explanation, Job Roles

Q:

There is 60% increase in an amount in 6 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate

A) Rs.4972	B) Rs.3972
C) Rs.5972	D) Rs.2972

Answer & Explanation Answer: B) Rs.3972

Explanation:

Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.

R= $\frac{100 * 60}{100 * 6}$ =10% p.a

Now, P = Rs. 12000. T = 3 years and R = 10% p.a.

C.I= $R s . [12000 * {[1 + \frac{10}{100}]}^{3} - 1]$
=Rs.3972

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

52 44367

Q:

Find the odd man out of the following number series?

1/2, 1, 3/2, 6, 5/2, 3

A) 1	B) 6
C) 5/2	D) 3/2

Answer & Explanation Answer: B) 6

Explanation:

The given series is 1/2, 1, 3/2, 6, 5/2, 3

1/2

1/2 + 1/2 = 1

1 + 1/2 = 3/2

3/2 + 1/2 = 2 (Not 6)

2 + 1/2 = 5/2

5/2 + 1/2 = 3

Hence, the odd man in the given number series is 6.

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Filed Under: Odd Man Out
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

1 44319

Q:

If 1 1 1 1 = R
2 2 2 2 = T
3 3 3 3 = E
4 4 4 4 = N

Then 5 5 5 5 = ?

A) Y	B) Z
C) T	D) X

Answer & Explanation Answer: A) Y

Explanation:

If you add all the terms of the LHS of equality, then the last letter of the sum written in words would give you the RHS.

1 + 1 + 1 + 1 = 4 = FOUR

2 + 2 + 2 + 2 = 8 = EIGHT

3 + 3 + 3 + 3 = 12 = TWELVE

4 + 4 + 4 + 4 = 16 = SIXTEEN

So, following the same pattern.

5 + 5 + 5 + 5 = 20 = TWENTY

That gives us our answer to 5 5 5 5 = "Y".

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Filed Under: Number Puzzles
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE , TOEFL
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86 43956

Q:

A person borrows Rs. 5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at $6 \frac{1}{4}$ p.a for 2 years. Find his gain in the transaction per year

A) Rs. 112.50	B) Rs.150.25
C) Rs.167.50	D) Rs.170

Answer & Explanation Answer: A) Rs. 112.50

Explanation:

$g a i n i n 2 y e a r s = R s . [(5000 * \frac{25}{4} * \frac{2}{100}) - (\frac{5000 * 4 * 2}{100})]$

= Rs. (625 - 400)

= Rs. 225

$g a i n i n 1 y e a r = R s . (\frac{225}{2}) = 112.50$

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

124 43954

Q:

The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs. 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

A) 20	B) 200
C) 300	D) 400

Answer & Explanation Answer: B) 200

Explanation:

Let length of plot = L meters, then breadth = L - 20 meters

and perimeter = 2[L + L - 20] = [4L - 40] meters

[4L - 40] * 26.50 = 5300

[4L - 40] = 5300 / 26.50 = 200

4L = 240

L = 240/4= 60 meters.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

30 43828

Q:

A school has four sections A, B, C, D of Class IX students.

1. If the number of students passing an examination be considered a criteria for comparision of difficulty level of two examinations, which of the following statements is true in this context?

A. Half yearly examinations were more difficult.

B. Annual examinations were more difficult.

C. Both the examinations had almost the same difficulty level.

D. The two examinations cannot be compared for difficulty level.

2. How many students are there in Class IX in the school?

A. 336 B.189 C. 335 D. 430

3. Which section has the maximum pass percentage in at least one of the two examinations?

A. A Section B. B Section C. C Section D. D Section

4. Which section has the maximum success rate in annual examination?

A. A Section B. B Section C. C Section D. D Section

5. Which section has the minimum failure rate in half yearly examination?

A. A section B. B section C. C section D. D section

Half yearly examinations were more difficult.

If the number of students passing an examination be considered a criteria for comparision of difficulty level of two examinations, which of the following statements is true in this context? - See more at: https://www.theonlinetestcentre.com/table-charts7.html#sthash.slrcbjro.dpuf

Answer

1. ANSWER : C

Explanation - Number of students who passed half-yearly exams in the school

= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)
= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true.

2. ANSWER : D

Explanation - Since the classification of the students on the basis of their results and sections form independent groups, so the total number of students in the class:

= (28 + 23 + 17 + 27 + 14 + 12 + 8 + 13 + 6 + 17 + 9 + 15 + 64 + 55 + 46 + 76)

= 430.

3. ANSWER : D

Explanation- Pass percentages in at least one of the two examinations for different sections are:

For Section A = $\frac{14 + 6 + 64}{28 + 14 + 6 + 64} \times 100 = \frac{84}{112} \times 100$ % = 75%

For Section B = $\frac{12 + 17 + 55}{23 + 12 + 17 + 55} \times 100$ % = 78.5%

For Section C = $\frac{8 + 9 + 46}{17 + 8 + 9 + 46} \times 100$ %= 78.75%

For Section D = $\frac{13 + 15 + 76}{27 + 13 + 15 + 76} \times 100$ %= 79.39%

Clearly ,the pass percentage is maximum for Section D

4. ANSWER : A

Explanation - Total number of students passed in annual exams in a section

= [ (No. of students failed in half-yearly but passed in annual exams) + (No. of students passed in both exams) ] in that section

Success rate in annual exams in Section A= $\frac{14 + 64}{112} \times 100$ % = 69.64%

Similarly, success rate in annual exams in:

Section B = $\frac{12 + 55}{107} \times 100$ % = 62.62%

Section C = $\frac{8 + 46}{80} \times 100$ % = 67.5%

Section D = $\frac{89}{131} \times 100$ % = 67.94%

Clearly, the success rate in annual examination is maximum for Section A.

5. ANSWER : D

Explanation - Total number of failures in half-yearly exams in a section

= [ (Number of students failed in both exams) + (Number of students failed in half-yearly but passed in Annual exams) ] in that section

Failure rate in half-yearly exams in Section A %= 37.5 %

Similarly, failure rate in half-yearly exams in:

Section B = 32.71%

Section C = 31.25%

Section D = 30.53%

Clearly, the failure rate is minimum for Section D.

= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)

= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true.

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Subject: Table Charts Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

138 43826

Q:

Which of the following is a popular programming language for developing multimedia webpages.

A) COBOL	B) Java
C) BASIC	D) Assembler

Answer & Explanation Answer: B) Java

Explanation:

Java is a general-purpose computer-programming language that is concurrent, class-based, object-oriented, and specifically designed to have as few implementation dependencies as possible.

Which_of_the_following_is_a_popular_programming_language_for_developing_multimedia_webpages1548652333.jpg image

Java is used to develop mobile apps, web apps, desktop apps, games and much more...

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Filed Under: Computer
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Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer , Network Engineer , Project Manager , Software Architect

180 43596

Q:

I go in dry and come out wet, The longer I’m in, the stronger it will get.

What am I?

A) Soap	B) Brush
C) Tea bag	D) All of the above

Answer & Explanation Answer: C) Tea bag

Explanation:

Tea bag is what it will go in dry and come out wet, the longer it is in, the stronger the tea we will get.

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Filed Under: Word Puzzles
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

14 43340

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