Bank PO Questions

                      Article I                   Article II
                         -20                         25%
                                        5%
                         20%                       25%
                     

                          4              :              5

Now, Selling of first article = (4-20%) = 0.8

Selling of second article = (5+25%) =  6.25

Therefore the ratio of selling price = 8 : 62.5

Here total parts of milk and water in the solution is 6+2 = 8 parts.

1part = 640/8 = 80

old mixture contains 6parts of milk and 2 parts of water(6:2).

To get new mixture containing half milk and half water, add 4parts of water to the old mixture then 6:(2+4) to make the ratio same.

i.e, 4 x 80 = 320 ml.

Let the total number of votes polled in the election be 100k.
Number of valid votes = 100k - 20% (100k) = 80k
Let the number of votes polled in favour of K and L be a and b respectively.
a - b = 15% (100k) => a = b + 15k
=> a + b = b + 15k + b
Now, 2b + 15k = 80k and hence b = 32.5k
It is given that 100k = 8720
32.5k = 32.5k/100k x 8720 = 2834

The number of valid votes polled in favour of L is 2834.

The Logic followed in the given puzzle is :

L x P = 12 x 16 = 192 (Alphabetical numbers of L & P)

P x T = 16 x 20 = 320 (Alphabetical numbers of P & T)

Similarly, K x () = 132 => () = 132/11 = 12 => L

Hence, the missing letter is L

Since each number to be divisible by 5, we must have 5 0r 0 at the units place. But in given digits we have only 5.

So, there is one way of doing it.

Tens place can be filled by any of the remaining 5 numbers.So, there are 5 ways of filling the tens place.

The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.

Required number of numbers = (1 x 5 x 4) = 20.

Word length refers to the number of bits processed by a computer's CPU in one go. These days, typically 32 bits or 64 bits are used.

Data bus size, instruction size, address size are usually multiples of the word size.

Let the speed of current = 'C' km/hr

Given the speed of boat in still water = 6 kmph

Let 'd' kms be the distance it covers.

According to the given data,

Boat takes thrice as much time in going the same distance against the current than going with the current

i.e, d8 - C = 3 × d8 + C

$$\begin{gathered} ⇒ 24 - 3C = 8 + C \\ ⇒ 4C = 16 \\ ⇒ C = 4 kmph \end{gathered}$$

Hence, the speed of the current C = 4 kmph.