Bank PO Questions


Q:

At an examination in which maximum marks are 500. P got 10% less than Q, Q got 25% more than R and R got 20% less than S. If P got 360 marks what percentage of marks was obtained by S ?

A) 77 B) 74
C) 80 D) 83
 
Answer & Explanation Answer: C) 80

Explanation:

Let marks obtained by S = M

R's marks = 0.80M

Q's marks = 1.25 (0.80M)

P's marks = (0.90) (1.25) (0.80M)

= 0.9M

But 0.9M = 360

M = ?

M = 400

Hence % of marks obtained by S

= 400/500 x 100 = 80%.

Report Error

View Answer Report Error Discuss

Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

11 12674
Q:

A driver of auto rickshaw makes a profit of 20% on every trip when he carries 3 passengers and the price of petrol is Rs. 30 a litre. Find the % profit for the same journey if he goes for 4 passengers per trip and the price of petrol reduces to Rs. 24 litres ?

A) 68% B) 80%
C) 75% D) 100%
 
Answer & Explanation Answer: D) 100%

Explanation:

When 3 passengers income was 3x
expense= Rs.30 
profit =20% of 30 = Rs.6 
That means his earning is Rs.36. so that per passenger fare must be Rs.12.

When 4 passengers
earning = 12x4=Rs.48.
expense =Rs.24.
profit = Rs.24 = 100%

Report Error

View Answer Report Error Discuss

Filed Under: Profit and Loss
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

19 12674
Q:

Two solutions have milk & water in the ratio 7:5 and 6:11. Find the proportion in which these two solutions should Be mixed so that the resulting solution has 1 part milk and 2 parts water ?

A) 7 : 12 B) 8 : 13
C) 9 : 4 D) 2 : 5
 
Answer & Explanation Answer: B) 8 : 13

Explanation:

To get the solution that contains 1 part of milk and two parts of water,
they must be mixed in the ratio as
7x+6x/5y+11y = 1/2
26x = 16y
x/y = 16/26
x/y = 8/13

Report Error

View Answer Report Error Discuss

Filed Under: Ratios and Proportions
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

19 12672
Q:

One-quarter of one-seventh of a land is sold for Rs. 30,000. What is the value of an four fifteenth of land ?

A) Rs.1,92,000 B) Rs.2,24,000
C) Rs.1,26,000 D) Rs.3,42,000
 
Answer & Explanation Answer: B) Rs.2,24,000

Explanation:

One-quarter of one-seventh = 1/4 x 1/7
= 1/28
Now, 1/28 of a land costs = Rs. 30,000
Thus, 8/35 of the land will cost = 30,000 x 28 x 4/15
= Rs. 2,24,000.

Report Error

View Answer Report Error Discuss

Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

15 12667
Q:

A trader marked the price of the T.V. 30% above the cost price of the T.V. and gave the purchaser 10% discount on the marked price, thereby gaining Rs.340. Find the cost price of the T.V ?

A) Rs. 2000 B) Rs. 1600
C) Rs. 2200 D) Rs. 2100
 
Answer & Explanation Answer: A) Rs. 2000

Explanation:

Let 'x' be the cost price.
Now Marked price = x + 30x/100 = 13x/10
10% discount = 10/100 x 13x/10 = 13x/100
Selling price = 13x/10 - 13x/100 = 117x/100
Given gain = 340
Here gain = 117x/100 - x = 17x/100 = 340 => x = Rs. 2000.

Report Error

View Answer Report Error Discuss

Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

13 12648
Q:

Rajeev start a business with Rs. 10000, Deepu joins him after 2 month with 20% more investment than Rajeev, after 2 month Shakti joins him with 40% less than Deepu. If the profit earned by them at the end of the year is equal to the twice of the difference between investment of Rajeev and ten times the investment of Shakti. Find the profit of Rajeev ?

A) 50000 B) 48000
C) 38000 D) 40000
 
Answer & Explanation Answer: C) 38000

Explanation:

Here from the given information,

The ratio of investments of Rajeev, Deepu & Shakti is

R : D : S = (10000 × 12) : (12000 × 10) : (7200 × 8)

= 25 : 25 : 12

Now the Profit = 2 × (72000-10000) = 124000

Share of Rajeev = 124000 x 25/62 = 48000

Profit of Rajeev = 48000 - 10000 = 38000

Report Error

View Answer Report Error Discuss

Filed Under: Partnership
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

21 12646
Q:

Chief component of first generation computer was

A) Vacuum tubes B) integrated circuits
C) transisters D) None of the above
 
Answer & Explanation Answer: A) Vacuum tubes

Explanation:

chief_component_of_first_generation_computer_was1538216221.jpg image

 

The chief component in the first generation computers are  Vacuum tubes.

Report Error

View Answer Report Error Discuss

Filed Under: Computer
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

16 12620
Q:

The area of a field in the shape of a trapezium measures 1440sq m. The perpendicular distance between its parallel sides is 24cm. If the ratio of the sides is 5:3, the length of the longer parallel side is:

A) 75 B) 85
C) 95 D) 105
 
Answer & Explanation Answer: A) 75

Explanation:

Area of field = 12*5x+3x*24 = 96x sq.m  

96x = 1440       => x =144096 = 15  

Hence, the length of longer parallel side = 5x = 75m

Report Error

View Answer Report Error Discuss

Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

7 12612