Bank PO Questions


Q:

A company requires 12,100 strength. Present employees are 400 ladies and 6400 gents. To reach the target how many ladies required to maintain the same ratio ?

A) 400 B) 600
C) 900 D) 700
 
Answer & Explanation Answer: C) 900

Explanation:

6,400 gents, 2400 ladies in that company.
So total 8,800employees.
for 8,800 employees, we want 2400 ladies.
for 12,100employees we want how many ladies ?
=> (12,100/8,800) x 2400 = 3300.
So we want 3300 - 2400 = 900 more ladies.

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Filed Under: Ratios and Proportions
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Q:

It costs Rs. p each to send the first thousand messsages and Rs. q to send each subsequent one . If r is greater than 1,000, how many Rupees will it cost to send r messages ?

A) 1000 (r - p) + pq B) 1000 p + qr
C) 1000 (r - q) + pr D) 1000(p - q) + qr
 
Answer & Explanation Answer: D) 1000(p - q) + qr

Explanation:

We need to find the total cost to send r messsages, r > 1000.

The first 1000 messsages will cost Rs.p each (Or) 

The total cost of first 1000 messsages = Rs.1000p

The remaining (r - 1000) messsages will cost Rs.q each (Or)

The cost of the (r - 1000) = Rs.(r - 1000)y

 

Therefore, total cost = 1000p + rq - 1000q

= 1000(p - q) + qr

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Q:

Two boys are playing on a ground. Both the boys are less than 10 years old. Age of the younger boy is equal to the cube root of the product of the age of the two boys. If we place the digit representing the age of the younger boy to the left of the digit representing the age of the elder boy, we get the age of the father of the younger boy. Similarly, we place the digit representing the age of the elder boy to the left of the digit representing the age of the younger boy and divide the figure by 2, we get the age of the mother of the younger boy. The mother of the younger boy is younger than his father by 3 years. Then, what are the ages of elder and younger boys ?

A) E = 15 & Y = 3 B) E = 14 & Y = 12
C) E = 40 & Y = 22 D) E = 4 & Y = 2
 
Answer & Explanation Answer: D) E = 4 & Y = 2

Explanation:

Let the the age of the elder boy = E

 

Let the the age of the younger boy = Y

 

Given that Y = cube root of EY

 


=> Y3 = EY => E = Y2 .....(1)
By the condition of number replacement the age of the father is YE

 

The Mother's age = EY/2

 

But she is 3 years less than father => EY/2 + 3 = YE
2YE = EY + 6 ......(2)

 

Then now from the given options we can identify which satisfies the all the conditions.

 

Here Y =2 and E = 4 satisfies all the conditions.

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Filed Under: Problems on Ages
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Q:

Ayush was born two years after his father's marriage. His mother is five years younger than his father but 20 years older than Ayush who is 10 years old. At what age did the father get married ?

A) 25 years B) 24 years
C) 23 years D) 22 years
 
Answer & Explanation Answer: C) 23 years

Explanation:

Ayush's present age = 10 years.
His mother's present age = (10 + 20) years = 30 years.
Ayush's father's present age = (30 + 5) years = 35 years.
Ayush's father's age at the time of Ayush's birth = (35 - 10) years = 25 years.

Therefore Ayush's father's age at the time of marriage = (25 - 2) years = 23 years.

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Filed Under: Problems on Ages
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Q:

An individual deposited 20% of 25% of 30% of what he had into his account with a bank. If he deposited Rs.750, how much was he having initially with him before depositing ?

A) Rs. 38000 B) Rs. 47000
C) Rs. 50000 D) Rs. 35000
 
Answer & Explanation Answer: C) Rs. 50000

Explanation:

Let 'x' be the amount he had in the bank.

=> 20/100(25/100(30/100(x))) = 750

x = 750 x 8000/120 = Rs. 50000

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Filed Under: Percentage
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Q:

Compound interest on a certain sum of money at 20% per annum for 2 years is Rs.5995. What is the SI on the same money at 8% per annum for 6 years ?

A) Rs. 5989 B) Rs. 6540
C) Rs. 7844 D) Rs. 6789
 
Answer & Explanation Answer: B) Rs. 6540

Explanation:

Given C.I = 5984, R = 20% , T = 2yrs

 C.I = P1+201002-1

 

5984 = 

 

=> P = (5995x25)/11

 

P = Rs. 13625

 

Now S.I = PTR/100

 

SI = (13625 x 8 x 6)/100 = Rs. 6540

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Filed Under: Compound Interest
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Q:

A wheelchair slalom event, athletes weave around cones and race to the finish line. A diagram of the rectangular course 30m length &16m bredth is shown. Find the the area of the course

A) 480 B) 560
C) 180 D) 460
 
Answer & Explanation Answer: A) 480

Explanation:

A = lw

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Q:

Which element has similar properties to Beryllium?

A) Manganese B) Calcium
C) Both A & B D) Helium
 
Answer & Explanation Answer: B) Calcium

Explanation:

The elements in the same column will have similar properties. Beryllium is the group II element. Group II elements are magnesium, calcium, strontium, barium and radium. Hence, these show the similar prperties.

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Filed Under: Chemistry
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