Bank PO Questions


Q:

The average age of a class is 19 years. While the average age of girls is 18 and that of boys is 21. If the number of girls in the class is 16, Find the number of Boys in the class?

A) 12 B) 10
C) 8 D) 6
 
Answer & Explanation Answer: C) 8

Explanation:

Let the number of boys = x

From the given data,

=> [21x + 16(18)]/(x+16) = 19

=> 21x - 19x = 19(16) - 16(18)

=> 2x = 16

=> x = 8

Therefore, the number of boys in the class = 8.

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Filed Under: Average
Exam Prep: AIEEE , Bank Exams , CAT
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23 12561
Q:

If you deposit $5000 into an account paying 6% annual interest compounded monthly, how long until there is $8000 in the account?

A) 6.9 B) 7.9
C) 8.9 D) 9.9
 
Answer & Explanation Answer: B) 7.9

Explanation:

 

 

FV=P(1+r/n)^nt

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

16 12550
Q:

How many iron rods, each of length 7 mts and diameter 2 cms can be made out of 0.88 cubic metre of iron ?

A) 500 B) 600
C) 400 D) 300
 
Answer & Explanation Answer: C) 400

Explanation:

Given length of iron rod =7 mts and  and diameter of rod = 2 cms 

=> r = 1/100 mts

Therefore,  Volume of one rod = πr2h cu. m =  227×11002×7cu. m = 115000 cu. m

Given volume of iron = 0.88 cu. m 

Therefore, Number of rods = 0.88×500011 = 400.

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Filed Under: Volume and Surface Area
Exam Prep: CAT
Job Role: Bank PO

17 12536
Q:

A number increased by 30% gives 390. The number is

A) 180 B) 300
C) 480 D) 260
 
Answer & Explanation Answer: B) 300

Explanation:

Let the number be 'N'
Given N + 30N/100 = 390
=> 130N/100 = 390
=> N = 390 x 10/13
=> N = 300.

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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16 12525
Q:

Rs. 2600 is divided into three parts A, B and C. How much A is more than C if their ratio is 1/2:1/3:1/4 ?

A) 600 B) 300
C) 150 D) 75
 
Answer & Explanation Answer: A) 600

Explanation:

1/2:1/3:1/4 = 6:4:3

As the difference is 3

=> 3/13x2600 = 600

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Filed Under: Ratios and Proportions
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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20 12520
Q:

Arrange the given words in alphabetical order and tick the one that comes in the middle ?

A) Slaughter B) Skirt
C) Straight D) Shout
 
Answer & Explanation Answer: A) Slaughter

Explanation:

The arrangement in the alphabetical order is Shout, Skirt, Slaughter, Specify, Straight.

The word in the middle is Slaughter.

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Filed Under: Alphabet Test
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20 12495
Q:

Garampani sanctuary is located at

A) Diphu, Assam B) Gangtok, Sikkim
C) Junagarh, Gujarat D) Kohima, Nagaland
 
Answer & Explanation Answer: A) Diphu, Assam

Explanation:

Famous for Hot water springs and homeland for Hoolock Gibbons and Golden Langurs, The Garampani Wildlife Sanctuary is situated in Karbi Anglong of Diphu area. One of the oldest Sanctuary containing Hot water spring and waterfalls and surrounded by Nambour Sanctuary having 51 rare species of Orchid. It has a total area of 6 sq. Km.

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Filed Under: General Science
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

30 12493
Q:

There are 6561 balls are there out of them 1 is heavy. Find the minimum number of times the balls have to be weighted for finding out the heavy ball ?

A) 2414 B) 204
C) 87 D) 8
 
Answer & Explanation Answer: D) 8

Explanation:

Suppose there are 9 balls

 

Let us give name to each ball B1 B2 B3 B4 B5 B6 B7 B8 B9

 

Now we will divide all the balls into 3 groups.

 

Group1 - B1 B2 B3

 

Group2 - B4 B5 B6

 

Group3 - B7 B8 B9

 

Step1 - Now weigh any two groups. Let's assume we choose Group1 on left side of the scale and Group2 on the right side.

 

So now when we weigh these two groups we can get 3 outcomes.

 

Weighing scale tilts on left - Group1 has a heavy ball.
Weighing scale tilts on right - Group2 has a heavy ball.
Weighing scale remains balanced - Group3 has a heavy ball.
Lets assume we got the outcome as 3. i.e Group 3 has a heavy ball.

 

Step2 - Now weigh any two balls from Group3. Lets assume we keep B7 on left side of the scale and B8 on right side.

 

So now when we weigh these two balls we can get 3 outcomes.

 

Weighing scale tilts on left - B7 is the heavy ball.
Weighing scale tilts on right - B8 is the heavy ball.
Weighing scale remains balanced - B9 is the heavy ball.
The conclusion we get from this Problem is that each time weigh. We element 2/3 of the balls.

 

As we came to conclusion that Group3 has the heavy ball from Step1, we remove 6 balls from the equation i.e (2/3) of 9.

 

Simillarly we do the ame thing for the Step2.

 

Now going with this conclusion. We have 6561 balls.

 

Step - 1

 

Divided into 3 groups

 

Group1 - 2187Balls

 

Group2 - 2187Balls

 

Group3 - 2187Balls

 

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

 

Step - 2

 

Divided into 3 groups

 

Group1 - 729Balls

 

Group2 - 729Balls

 

Group3 - 729Balls

 

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

 

Step - 3

 

Divided into 3 groups

 

Group1 - 243Balls

 

Group2 - 243Balls

 

Group3 - 243Balls

 

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

 

Step - 4

 

Divided into 3 groups

 

Group1 - 81Balls

 

Group2 - 81Balls

 

Group3 - 81Balls

 

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

 

Step - 5

 

Divided into 3 groups

 

Group1 - 27Balls

 

Group2 - 27Balls

 

Group3 - 27Balls

 

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

 

Step - 6

 

Divided into 3 groups

 

Group1 - 9Balls

 

Group2 - 9Balls

 

Group3 - 9Balls

 

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

 

Step - 7

 

Divided into 3 groups

 

Group1 - 3Balls

 

Group2 - 3Balls

 

Group3 - 3Balls

 

Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.

 

Step - 8

 

So now when we weigh 2 balls out of 3 we can get 3 outcomes.

 

Weighing scale tilts on left - left side placed is the heavy ball.
Weighing scale tilts on right - right side placed is the heavy ball.
Weighing scale remains balanced - remaining ball is the heavy ball.
So the general answer to this question is, it is always multiple of 3 steps.

 

For 9 balls  32= 9. therefore 2 steps

 

For 6561 balls 38 = 6561 therefore 8 steps

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Filed Under: Arithmetical Reasoning
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