Bank Clerk Questions


Q:

Calculate the number of bricks, each measuring 25 cm x 15 cm x 8 cm required to construct a wall of dimensions 10 m x 4 cm x 6 m when 10% of its volume is occupied by mortar  ?

A) 720 B) 600
C) 660 D) 6000
 
Answer & Explanation Answer: A) 720

Explanation:

Let the number of bricks be 'N'

10 x 4/100 x 6 x 90/100 = 25/100 x 15/100 x 8/100 x N

10 x 4 x 6 x 90 = 15 x 2 x N => N = 720.

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Filed Under: Area
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

6 8603
Q:

The length of a class room floor exceeds its breadth by 25 m. The area of the floor remains unchanged when the length is decreased by 10 m but the breadth is increased by 8 m. The area of the floor is 

A) 5100 sq.m B) 4870 sq.m
C) 4987 sq.m D) 4442 sq.m
 
Answer & Explanation Answer: A) 5100 sq.m

Explanation:

Let the breadth of floor be 'b' m.

Then, length of the floor is 'l = (b + 25)'

Area of the rectangular floor = l x b = (b + 25) × b

According to the question,

(b + 15) (b + 8) = (b + 25) × b

b2 + 8b + 15b + 120 = b2 + 25b

2b = 120

b = 60 m.

l = b + 25 = 60 + 25 = 85 m.

 

Area of the floor = 85 × 60 = 5100 sq.m.

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Filed Under: Area
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , IT Trainer

37 8596
Q:

Hari Ram’s present age is three times his son’s present age and two fifth of his father’s present age. The average of the present age of all of them is 46 years. What is the difference between Hari Ram’s son’s present age and Hari Ram’s father’s present age? 

A) 44 yrs B) 56 yrs
C) 67 yrs D) 78 yrs
 
Answer & Explanation Answer: D) 78 yrs

Explanation:

Let Hari Ram's present age = x

Then, his son's age = x/3

Father's age = 5x/2

x + x3 + 52x3 = 46=> x = 36 yrs

Now the required difference = 52x36 - 363 = 78 yrs

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

11 8594
Q:

If 12 men can reap 120 acres of land in 36 days, how many acres of land can 54 men reap in 54 days?

A) 710 acres B) 760 acres
C) 810 acres D) 860 acres
 
Answer & Explanation Answer: C) 810 acres

Explanation:

12 men120 acres36 days54 men?54 days

 As 12 men can reap 120 acres, 54 men will be able to reap more acres in 36 days, 120 acres of land was reaped, so in 54 days, more land will be reaped.

 

Thus, the numbers of acres that can be reaped by 54 men in 54 days = 5412x120x5436 = 810 acres

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Filed Under: Ratios and Proportions
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

19 8588
Q:

A box contains 4 different black balls, 3 different red balls and 5 different blue balls. In how many ways can the balls be selected if every selection must have at least 1 black ball and one red ball ?

A) 24 - 1  

B) 2425-1   

C) (24-1)(23-1)25   

D) None 

A) A B) B
C) C D) D
 
Answer & Explanation Answer: C) C

Explanation:

It is explicitly given that all the 4 black balls are different, all the 3 red balls are different and all the 5 blue balls are different. Hence this is a case where all are distinct objects.

 

Initially let's find out the number of ways in which we can select the black balls. Note that at least 1 black ball must be included in each selection.

 

Hence, we can select 1 black ball from 4 black balls
or 2 black balls from 4 black balls.
or 3 black balls from 4 black balls.
or 4 black balls from 4 black balls.

 

Hence, number of ways in which we can select the black balls

 

= 4C1 + 4C2 + 4C3 + 4C4
= 24-1 ........(A)

 

Now let's find out the number of ways in which we can select the red balls. Note that at least 1 red ball must be included in each selection.

 

Hence, we can select 1 red ball from 3 red balls
or 2 red balls from 3 red balls
or 3 red balls from 3 red balls

 

Hence, number of ways in which we can select the red balls
= 3C1 + 3C2 + 3C3
=23-1........(B)

 

Hence, we can select 0 blue ball from 5 blue balls (i.e, do not select any blue ball. In this case, only black and red balls will be there)
or 1 blue ball from 5 blue balls
or 2 blue balls from 5 blue balls
or 3 blue balls from 5 blue balls
or 4 blue balls from 5 blue balls
or 5 blue balls from 5 blue balls.

 

Hence, number of ways in which we can select the blue balls
= 5C0 + 5C1 + 5C2 + … + 5C5
= 25..............(C)

 

From (A), (B) and (C), required number of ways
=  2524-123-1

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Filed Under: Permutations and Combinations
Exam Prep: GATE , CAT , Bank Exams , AIEEE
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3 8584
Q:

If the first and second digits are interchanged in each number from the following set of numbers, and then the numbers are arranged in descending order, which number will be second ?

376  438  476  389  567

A) 376 B) 567
C) 389 D) 476
 
Answer & Explanation Answer: D) 476

Explanation:

Given 376  438  476  389  567 

 

After interchanging 1st and 2nd digits

 

736  348  746  839  657  

 

Now, arranging in descending order 839  746  736  657  348 

 

Here in second place 746

 

Therefore, 476 is the answer.

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Filed Under: Logical Sequence of Words
Exam Prep: Bank Exams
Job Role: Bank Clerk

20 8580
Q:

Each consonant in the word TIRADES is replaced by the previous letter in the English alphabet and each vowel is replaced by the next letter in the English alphabet and the new letters are arranged alphabetically. Which of the following will be the fourth from the right end ?

A) S B) Q
C) J D) U
 
Answer & Explanation Answer: C) J

Explanation:

Given word is TIRADES
Now the consonants T, R, D, S are replaced by S, Q, C, R
And Vowels are I, A, E are replaced by J, B and F
They are arranged alphabetically
New word is BCFJQRS

The fourth letter from the right end is J.

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Filed Under: Alphabet Test
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
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9 8578
Q:

The average number of visitors of a library in the first 4 days of a week was 58. The average for the 2nd, 3rd, 4th and 5th days was 60.If the number of visitors on the 1st and 5th days were in the ratio 8 : 9. Then what is the number of visitors on the 5th day of the library ?

A) 54 B) 64
C) 68 D) 72
 
Answer & Explanation Answer: D) 72

Explanation:

If number of visitors on 1st, 2nd, 3rd, 4th & 5th day are k, l, m, n & o respectively, then
k + l + m + n = 58 x 4 = 232 ---- (i) &
l + m + n + o = 60 x 4 = 240 ---- (ii)
Subtracting (i) from (ii), we get
o-k = 8 ---(iii)
Given, k/o = 8/9 ----(iv)
So from (iii) & (iv), we get
a = 64, e = 72
Therefore, number of visitors on 5th day is 72.

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Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

8 8573