Analyst Questions

Let workdone 1 boy in 1 day be b

and that of 1 girl be g

From the given data,

4(5b + 3g) = 23

20b + 12g = 23 .......(a)

2(3b + 2g) = 7

6b + 4g = 7 ........(b)

Solving (a) & (b), we get

b = 1, g = 1/4

Let number og girls required be 'p'

6(7 x 1 + p x 1/4) = 45

=> p = 2.

Hence, number of girls required = 2

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Interest earned in scheme M =   

P1 + 201002 - 1 = 11P25

Interest earned in scheme N =  

P x k x 2100 = Pk50

Now, from the given data,

11P25 = 2 x Pk50

k = 11