Q:
In what time would a cistern be filled by three pipes which diameters are 2 cm, 3 cm and 4 cm running together, when the largest alone can fill it is 58 minutes? The amount of water flowing in each pipe is proportional to the square of its diameter.
Answer & Explanation
Answer: B) 32 min
Explanation: Given that the diameters of the three pipes are 2 cm, 3 cm and 4 cm
From the given data,
Amount of water from three pipes is 4 units, 9 units and 16 units.
Let the capacity of cistern be 'p' units.
∴ p/58 = 16
⇒ p = 928 units.
In 1 minute, quantity to be filled by 3 pipes = 29 units
∴ Total time required = 928/29 = 32 minutes.
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