Analyst Questions

A vector quantity is a quantity which has both magnitude and direction. Here in the given options, speed is a scalar quantity but not the vector quantity.

1. ANSWER : C 

 Explanation -  Number of students who passed half-yearly exams in the school 

= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)
= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true. 

 2. ANSWER : D 

 Explanation -  Since the classification of the students on the basis of their results and sections form independent groups, so the total number of students in the class: 

 = (28 + 23 + 17 + 27 + 14 + 12 + 8 + 13 + 6 + 17 + 9 + 15 + 64 + 55 + 46 + 76)

= 430. 

 3. ANSWER : D 

 Explanation- Pass percentages in at least one of the two examinations for different sections are:

  For Section A = 14+6+6428+14+6+64×100 = 84112×100% = 75%

 For Section B =12+17+5523+12+17+55×100 % = 78.5%

 For Section C = 8+9+4617+8+9+46×100%= 78.75%

 For Section D = 13+15+7627+13+15+76×100%= 79.39%

  Clearly ,the pass percentage is maximum for Section D 

 4. ANSWER : A

 Explanation - Total number of students passed in annual exams in a section 

= [ (No. of students failed in half-yearly but passed in annual exams) + (No. of students passed in both exams) ] in that section

 Success rate in annual exams in Section A= 14+64112 × 100% = 69.64%

 Similarly, success rate in annual exams in:

 Section B = 12+55107×100% =  62.62% 

 Section C = 8+4680×100% = 67.5% 

 Section D = 89131×100% = 67.94% 

 Clearly, the success rate in annual examination is maximum for Section A. 

 5. ANSWER : D 

 Explanation - Total number of failures in half-yearly exams in a section

  = [ (Number of students failed in both exams) + (Number of students failed in half-yearly but passed in Annual exams) ] in that section

 Failure rate in half-yearly exams in Section A %= 37.5 %

 Similarly, failure rate in half-yearly exams in:

  Section B = 32.71%

  Section C = 31.25%

  Section D = 30.53%

  Clearly, the failure rate is minimum for Section D.

 = (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)

 = (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

 = 288.

 Also, Number of students who passed annual exams in the school

 = (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

 = (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

 = 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true.

The given number series is 1, 3, 10, 41, 206, ?

It follows a pattern that,

1

1 x 2 + 1 = 3

3 x 3 + 1 = 10

10 x 4 + 1 = 41

41 x 5 + 1 = 206

206 x 6 + 1 = 1237

Hence, the next number in the given number series is 1237.

Given number of boxes = 14

Number of workers = 4

Now, number of whole boxes per worker = 14/4 = 3.5 

Hence, number of whole boxes per each coworker = 3

The given series is 8, 14, 24, 60, 180

8

8 x 1.5 = 12 (NOT 14)

12 x 2 = 24

24 x 2.5 = 60

60 x 3 = 180

Hence, the odd man in the given series is 12.

An idea for a Constituent Assembly of India was proposed in 1934 by M. N. Roy, a pioneer of the Communist movement in India and an advocate of radical democracy. It became an official demand of the Indian National Congress in 1935, C. Rajagopalachari voiced the demand for a constituent Assembly on 15 November 1939 based on adult franchise, and was accepted by the British in August 1940.

Under the Cabinet Mission Plan of 1946, elections were held for the first time for the Constituent Assembly. The Constitution of India was drafted by the Constituent Assembly, and it was implemented under the Cabinet Mission Plan on 16 May 1946.

The Constituent Assembly appointed a total of 22 committees to deal with different tasks of constitution-making. Out of these, eight were major committees and the others were minor committees.

The Major Committees and its Chairman's:: 

1. Drafting Committee – Dr. B.R. Ambedkar

2. Union Powers Committee – Jawaharlal Nehru

3. Union Constitution Committee – Jawaharlal Nehru

4. Provincial Constitution Committee – Sardar Patel

5. Advisory Committee on Fundamental Rights, Minorities and Tribal and Excluded Areas – Sardar Patel. This committee had the following subcommittees:
                   * Fundamental Rights Sub-Committee – J.B. Kripalani
                   * Minorities Sub-Committee – Harendra Coomar Mookerjee,
                   * North-East Frontier Tribal Areas and Assam Excluded & Partially Excluded Areas Sub-Committee – Gopinath Bardoloi
                   * Excluded and Partially Excluded Areas (Other than those in Assam) Sub-Committee – A V Thakkar

6. Rules of Procedure Committee – Dr. Rajendra Prasad

7. States Committee (Committee for Negotiating with States) – Jawaharlal Nehru

8. Steering Committee – Dr. Rajendra Prasad

Dr. Babasaheb Ambedkar, chairman of the Drafting Committee of Constituent Assembly of India.

When you develop a product, you assess its performance for proper functioning.

Similarly, when you train a person to do a job, you analyze his/her performance to understand how good he/she is at it.

Hence, Develop : Assess :: Train : Analyze.

Recall it is based on inverse proportion or product constancy concept.

     Reducion in price                      increase in amount

         25%     1/4                              1/3   33.33% = 4 oranges

It means original number of oranges = 4 x 3 = 12

original price of oranges = 16/12 = Rs. 1.33