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Q:

One side of a rectangular field is 15m and one of its diagonal is 17m. Find the area of field?

A) 110 B) 120
C) 130 D) 140
 
Answer & Explanation Answer: B) 120

Explanation:

Other side = [(17 x 17) - (15 x 15)] = (289 - 225) = 8m
Area = 15 x 8 =120 sq. m

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Q:

If the radius of a circle is decreased by 50%, find the percentage decrease in its area.

A) 55% B) 65%
C) 75% D) 85%
 
Answer & Explanation Answer: C) 75%

Explanation:

Let original radius = R. 

 

New radius = 50100R50100R 

 

Original area =R2  and new area = πR2

 

3πR24*1πR2*100 

 

Decrease in area = πR22=πR24 = 75%

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Q:

Find the ratio of the areas of the incircle and circumcircle of a square.

A) 1:1 B) 1:2
C) 1:3 D) 1:4
 
Answer & Explanation Answer: B) 1:2

Explanation:

Let the side of the square be x. Then, its diagonal = 2x2=2x 

Radius of incircle = x2 

Radius of circum circle= 2×x2=x2 

Required ratio = πx24:πx22=14:12=1:2

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Q:

A sector of 120, cut out from a circle, has an area of 667cm2. Find the radius of the circle ?

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: C) 3

Explanation:

Let the radius of the circle be r cm. Then, 

 

120360πr2=667 

 

r2=667*722*3 

 

r=3.

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Q:

Two concentric circles form a ring. The inner and outer circumferences of ring are  5187m and 3527 m respectively. Find the width of the ring.

A) 4 B) 5
C) 6 D) 7
 
Answer & Explanation Answer: A) 4

Explanation:

Let the inner and outer radii be r and R metres.

 

Then  2πR=3527=>R=3527*722*12=8m 

 

 2πR=5287=>R=5287*722*12=12m

 

=> Width of the ring = (R - r) = (12 - 8) m = 4 m.

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Q:

The inner circumference of a circular race track, 14 m wide, is 440 m. Find radius of the outer circle

A) 44 B) 22
C) 33 D) 84
 
Answer & Explanation Answer: D) 84

Explanation:

Let inner radius be r metres. Then, 2πr = 440 ; r = 440×744= 70 m.

Radius of outer circle = (70 + 14) m = 84 m.

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Q:

A wheel makes 1000 revolutions in covering a distance of 88 km. Find the radius of the wheel.

A) 14 B) 13
C) 12 D) 11
 
Answer & Explanation Answer: A) 14

Explanation:

Distance covered in one revolution = 88×10001000= 88m. 

 

2πR2=88  2×227×R=88  R=88×744

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Q:

The diameter of the driving wheel of a bus is 140 cm. How many revolution, per minute must the wheel make in order to keep a speed of 66 kmph ?

A) 150 B) 250
C) 350 D) 550
 
Answer & Explanation Answer: B) 250

Explanation:

Circumference = No.of revolutions * Distance covered

 

Distance to be covered in 1 min. = (66 X1000)/60 m = 1100 m.
Circumference of the wheel = 2 x (22/7) x 0.70 m = 4.4 m.
Number of revolutions per min. =(1100/4.4) = 250.

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