Q:
How many six digit odd numbers can be formed from the digits 0, 2, 3, 5, 6, 7, 8, and 9 (repetition not allowed)?
Answer & Explanation
Answer: A) 8640
Explanation: Let the 6 digits of the required 6 digit number be abcdef
Then, the number to be odd number the last digit must be odd digit i.e 3, 5, 7 or 9
The first digit cannot be ‘0’ => possible digits = 3, 5, 7, 2, 6, 8
Remaining 4 places can be of 6 x 5 x 4 x 3 ways
This can be easily understood by
Therefore, required number of ways = 6 x 6 x 5 x 4 x 3 x 4 = 36 x 20 x 12 = 720 x 12
= 8640 ways.
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