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Q:

The ratio of the area of a square to that of the square drawn on its diagonal is

A) 1:2 B) 2;3
C) 3:1 D) 4:1
 
Answer & Explanation Answer: A) 1:2

Explanation:

ratio = a22a2

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Q:

The area of a square field is 69696sq.cm..its diagonal will be equal to

A) 373 B) 573
C) 473 D) 673
 
Answer & Explanation Answer: A) 373

Explanation:

d=2*s=>d=2*69696

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Q:

If the length of the diagonal of a square is 20cm,then its perimeter must be

a. 402cm     b. 302cm    c. 10cm    d. 152cm

A) a B) b
C) c D) d
 
Answer & Explanation Answer: A) a

Explanation:

We know that d=√2s 

Given diagonal = 20 cm 

=> s = 20/2 cm

Therefore, perimeter of the square is 4s = 4 x 20/2 = 402   cm.

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Q:

The circumference of a circle, whose area is 24.64 sq.m

A) 14.64 B) 16.36
C) 17.60 D) 18.40
 
Answer & Explanation Answer: C) 17.60

Explanation:

πr2 =26.64

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Q:

The area of the circle is 220 sq.m, the area of the square inscribed in a circle will be

A) 49 B) 70
C) 140 D) 150
 
Answer & Explanation Answer: C) 140

Explanation:

area of a square = 12diagonal2

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Q:

The area of the largest circle that can be drawn inside a rectangle with sides 18cm by 14cm is

A) 49 B) 154
C) 378 D) 1078
 
Answer & Explanation Answer: B) 154

Explanation:

The diameter is equal to the shortest side of the rectangle.

 So radius= 14/2 = 7cm. 

Therefore,  area of circle =πr2=227×49=154cm2

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86 54132
Q:

At what time between 5.30 and 6 will the hands of a clock be at right angles?

A) (43 + 5/11) min past 5 B) (43 + 7/11) min pats 5
C) 5 D) 7
 
Answer & Explanation Answer: B) (43 + 7/11) min pats 5

Explanation:

At 5 o'clock, the hands are 25 min. spaces apart.
To be at right angles and that too between 5.30 and 6, the minute hand has to gain (25 + 15) = 40 min. spaces.

 

55 min. spaces are gained in 60 min

 

40 min. spaces are gained in 6055×40 min  

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Q:

At what time between 7 and 8 o'clock will the hands of a clock be in the same straight line but,not together?

A) (5 + 5/11 )min past 7 B) (6 + 5/11) min past 7
C) 7 D) 8
 
Answer & Explanation Answer: A) (5 + 5/11 )min past 7

Explanation:

When the hands of the clock are in the same straight line but not together, they are 30 minute spaces apart.
At 7 o'clock, they are 25 min. spaces apart.
Minute hand will have to gain only 5 min. spaces.
55 min. spaces are gained in 60 min.

 

5 min spaces are gained in 6055*5 min  = 5511min 

 

so, Required time = 5511 min  past 7

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