GRE Questions

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Let the number of sides be n. 

The number of diagonals is given by ⁿC₂ - n  

^{Therefore, n}C₂ - n = 44, n>0 

ⁿC₂ - n = 44

n² - 3n - 88 = 0 

n² -11n + 8n - 88 = 0  

As n>0, n will not be -8. Therefore, n=11.

Here, x = 20 and y = - 20
Therefore, the net % change in value
=x + y + xy100 %
= 20 + -20 + 20 × -20100%  or  - 4%

Since the sign is negative, there is a decrease in value by 4%.

Since S.P. = 5 (M.P. - S.P.) => 5 M.P. = 6 S.P.
M.P. = (6/5) S.P.
Since the percentage discount = Percentage profit,
65S.P - S.P65S.P×100 = S.P -C.PC.P×100
Therefore, 1/6 = (S.P/C.P) – 1 => S.P = (7/6) C.P
M.P = 6/5 S.P = 6/5 x 7/6 C.P = 7/5 C.P
Therefore, Ratio of discount to C.P
= (M.P – S.P)/C.P = [{(7/5)C.P - (7/6)C.P} / C.P.]
= 7/30

Therefore, the ratio is 7 : 30

Astronomy is the study of planets and heavenly bodies. Historically, astronomy has focused on observations of heavenly bodies. It is a close cousin to astrophysics. Succinctly put, astrophysics involves the study of the physics of astronomy and concentrates on the behavior, properties and motion of objects out there.
 

After falling it bruises, similarly after knocking it bumps.

Hence, Bruise : Fall :: Bump : Knock.

To get a pair of black rings 100 percent certain

27 blue + 17 red + 2 black = 40 rings should be taken out

Then only we can get 100 % a pair of black rings. 

Let x and y be the respective km's travelled by man via taxi and by his own car.
Given x + y = 90 => x = 90 - y
But according to the question,
7x + 6y = 595
7(90-y) + 6y = 595
=> 630 - 7y + 6y = 595
=> y = 630 - 595 = 35
=> x = 90 - 35 = 55
Therefore, the distance travelled by taxi is 55 kms.

Yard is to Inch as Quart is to Ounce.

Because Yard and Inch are units of measurement Where Yard is larger than Inch i.e, 1 Yard = 36 Inches.

So, here Quart and Ounce are also units of measurement where Quart is larger than Ounce i.e, 1 Quart = 32 Ounces.

Gallon is not correct because Gallon is larger than Quart and Milk and Liquid are not units of measurement.

So, Ounce is correct.