GRE Questions

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Let C.P. = Rs. C.
Then, 832 - C = C - 448
2C = 1280 => C = 640
Required S.P. = 150% of Rs. 640 = 150/100 x 640 = Rs. 960.

Since the narrator has no brother, his father’s son is he himself. So, the man who is talking is the father of the man in the photograph. Thus, the man in the photograph is his son.

principal = A=4913,T=3, R=413

P=A1+R100T

 = Rs.4096

C alone can finish the work in 40 days.
As given C does half as much work as A and B together
=> (A + B) can do it in 20 days
(A + B)s 1 days wok = 1/20.
A's 1 days work : B's 1 days Work = 1/2 : 1 = 1:2(given)
A's 1 day’s work = (1/20) x (1/3) = (1/60) [Divide 1/20 in the raio 1:2]
B's 1 days work = (1/20) x (2/3) = 1/30
(A+B+C)'s 1 day's work = (1/60) + (1/30) + (1/40) = 9/120 = 3/40

All the three together will finish it in 40/3 = 13 and 1/3 days.

Only one such symbol is there in the given arrangement.

It is 4@5.

S.I. = Rs. (15500 - 12500) = Rs. 3000.

Rate = 100*300012500*4 % = 6%

Let the total distance to be covered is 84 kms.
Time taken to cover the distance without stoppage = 84/42 hrs = 2 hrs
Time taken to cover the distance with stoppage = 84/28 = 3 hrs.
Thus, he takes 60 minutes to cover the same distance with stoppage.
Therefore, in 1 hour he stops for 20 minutes.

Given that the next word should start with the ending two letters of the previous word. From this,

The first word is

SHIVER

Now, the next word should start with ER and must contain OT in the middle.

EROTIC

Now, the next word should start with IC and must contain IC in the middle.

ICICLE

Now, the next word should start with LE and must contain NG in the middle.

LENGTH

Now, the next word should start with TH and must contain RA in the middle.

THRASH

Hence, the required five words are SHIVER, EROTIC, ICICLE, LENGTH, THRASH.