GRE Questions and Answers with Explanation

Q:

John sells his laptop to Mark at a loss of 20% who subsequently sells it to Kevin at a profit of 25%. Kevin after finding some defect in the laptop, returns it to Mark but could recover only Rs.4.50 for every Rs. 5 he had paid. Find the amount of Kevin’s loss if John had paid Rs. 1,75,000 for the laptop ?

A) Rs.16,500	B) Rs.17,500
C) Rs.14,200	D) Rs.15,520

Answer & Explanation Answer: B) Rs.17,500

Explanation:

Let’s assume John bought the laptop for Rs. 100
He then sells it to Mark at a loss of 20% => Rs. 80,
Who consequently sells it to Kevin at a profit of 25% => Rs. 100
Then, Kevin sells it back to Mark for Rs. 90 (Rs.4.50 for every Rs. 5 that he had paid initially), so he suffers a loss of Rs. 10
Therefore, for Rs. 100 there is a loss of Rs. 10,
Then for Rs. 1,75,000 there will be a loss of Rs. 17,500.

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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15 9743

Q:

Find: S.l on Rs 68000 at $16 \frac{2}{3}$ 1 % per annum for 9 months

A) 6500	B) 7500
C) 8500	D) 9500

Answer & Explanation Answer: C) 8500

Explanation:

P = 68000, R = $\frac{50}{3}$ % & T = 9 months (3/4 years)

$S . I = \frac{p \times r \times t}{100} = [\frac{(6800 \times \frac{50}{3} \times \frac{3}{4})}{100}] = R s . 8500$

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Filed Under: Simple Interest
Exam Prep: GRE
Job Role: Bank PO

3 9730

Q:

If a man buys 1 lt of milk for Rs.12 and mixes it with 20% water and sells it for Rs.15, then what is the percentage of gain ?

A) 25%	B) 30%
C) 17%	D) 19%

Answer & Explanation Answer: A) 25%

Explanation:

He has gain = 15 - 12 = 3,
Gain% = (3/12) x 100 = (100/4) = 25.
He has 25% gain.

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Filed Under: Alligation or Mixture
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17 9677

Q:

On a school’s Annual day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get ?

A) 14	B) 16
C) 12	D) 15

Answer & Explanation Answer: D) 15

Explanation:

Let 'K' be the total number of sweets.
Given total number of students = 112
If sweets are distributed among 112 children,
Let number of sweets each student gets = 'L'

=> K/112 = L ....(1)
But on that day students absent = 32 => remaining = 112 - 32 = 80
Then, each student gets '6' sweets extra.

=> K/80 = L + 6 ....(2)
from (1) K = 112L substitute in (2), we get
112L = 80L + 480
32L = 480
L = 15

Therefore, 15 sweets were each student originally supposed to get.

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Filed Under: Average
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10 9658

Q:

There is 50% increase in an amount in 5 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate ?

A) Rs. 5422	B) Rs. 5489
C) Rs. 3972	D) Rs. 6145

Answer & Explanation Answer: C) Rs. 3972

Explanation:

Let p = Rs. 100.

Then, S.I is Rs. 50 and time = 5 years.

$∴ R = \frac{100 \times 50}{100 \times 5}$ = 10% p.a.

Now, p = Rs. 12,000 , T = 3 years and R = 10% p.a.

C.I. = Rs. $12000 \times \{{(1 + \frac{10}{100})}^{3} - 1\}$ = Rs. 3972

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Filed Under: Compound Interest
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7 9632

Q:

Microphone : Loud :: Microscope : ?

A) Investigate	B) Magnify
C) Examine	D) Elongate

Answer & Explanation Answer: B) Magnify

Explanation:

As Microphone makes sound louder similarly Microscope makes the object magnified.

Hence, Microphone : Loud :: Microscope : Magnify.

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Filed Under: Analogy
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5 9621

Q:

What is the sum which earned interest?
I. The total simple interest was Rs. 7000 after 7 years.
II. The total of sum and simple interest was double of the sum after 5 years.

A) I alone sufficient while II alone not sufficient to answer	B) II alone sufficient while I alone not sufficient to answer
C) Either I or II alone sufficient to answer	D) Both I and II are necessary to answer

Answer & Explanation Answer: D) Both I and II are necessary to answer

Explanation:

Let the sum be Rs. x.

I gives, S.I. = Rs. 7000 and T = 7 years.

II gives, Sum + S.I. for 5 years = 2 x Sum Sum = S.I. for 5 years.

Now, S.I. for 7 years = Rs. 7000.

therefore, S.I. for 1 year = Rs. 1000.

Thus, I and II both are needed to get the answer.

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Filed Under: Simple Interest
Exam Prep: GRE
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3 9614

Q:

The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles ?

A) 2413 sq.m	B) 1234 sq.m
C) 4312 sq.m	D) 2143 sq.m

Answer & Explanation Answer: C) 4312 sq.m

Explanation:

Let the radii of the smaller and the larger circles be 's' m and 'l' m respectively.

$2 πs$ = 264 and $2 πl$ = 352

s = $\frac{264}{2 π}$ and l = $\frac{352}{2 π}$

Difference between the areas = $π l^{2} - π s^{2}$

= $π (\frac{176^{2}}{π^{2}} - \frac{132^{2}}{π^{2}})$

= $\frac{1762}{π} - \frac{1322}{π}$

= (176 - 132)(176 + 132) / $π$

= (44 x 308) / (22/7) = 4312 sq.m

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Filed Under: Volume and Surface Area
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18 9576

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