GATE Questions

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C alone can finish the work in 40 days.
As given C does half as much work as A and B together
=> (A + B) can do it in 20 days
(A + B)s 1 days wok = 1/20.
A's 1 days work : B's 1 days Work = 1/2 : 1 = 1:2(given)
A's 1 day’s work = (1/20) x (1/3) = (1/60) [Divide 1/20 in the raio 1:2]
B's 1 days work = (1/20) x (2/3) = 1/30
(A+B+C)'s 1 day's work = (1/60) + (1/30) + (1/40) = 9/120 = 3/40

All the three together will finish it in 40/3 = 13 and 1/3 days.

Let C.P. = Rs. C.
Then, 832 - C = C - 448
2C = 1280 => C = 640
Required S.P. = 150% of Rs. 640 = 150/100 x 640 = Rs. 960.

Lover of nature is called nature lover or Green Panther.

Autophile is a person who loves being alone.

Dendrophile is a person who loves trees and forests.

Petrichor is an earthy smell that follows a rainfall.

Since the narrator has no brother, his father’s son is he himself. So, the man who is talking is the father of the man in the photograph. Thus, the man in the photograph is his son.

Let the total distance to be covered is 84 kms.
Time taken to cover the distance without stoppage = 84/42 hrs = 2 hrs
Time taken to cover the distance with stoppage = 84/28 = 3 hrs.
Thus, he takes 60 minutes to cover the same distance with stoppage.
Therefore, in 1 hour he stops for 20 minutes.

The given number series 999, 990, 998, 991, 997, 992, ?

It follows a pattern that,

999

999 - 9 = 990

990 + 8 = 998

998 - 7 = 991

991 + 6 = 997

997 - 5 = 992

992 + 4 = 996

Hence, the next number in the given number series is 996.

Given that the next word should start with the ending two letters of the previous word. From this,

The first word is

SHIVER

Now, the next word should start with ER and must contain OT in the middle.

EROTIC

Now, the next word should start with IC and must contain IC in the middle.

ICICLE

Now, the next word should start with LE and must contain NG in the middle.

LENGTH

Now, the next word should start with TH and must contain RA in the middle.

THRASH

Hence, the required five words are SHIVER, EROTIC, ICICLE, LENGTH, THRASH.

Let the amounts to be received by P, Q and R be p, q and r.
p + q + r = 1200
p = 1/2 (q + r) => 2p = q + r

Adding 'p' both sides, 3p = p + q + r = 1200
=> p = Rs.400

q = 1/3 (p + r) => 3q = p + r

Adding 'q' both sides, 4q = p + q + r = 1200
=> q = Rs.300

r = 1200 - (p + q) => r = Rs.500.