GATE Questions

---

Let the two conditioners be A and B

'A' cools at 40min

'B' at 45min

Together = (a x b)/(a + b)

= (45 x 40)/(45 + 40)

= 45 x 40/85

= 21.1764

= 22 min (approx).

Pour - 4156 => P = 4,  r = 6

Sware - 78269 => a =  2,  e = 9

Clear - 3@926 => l = @

=> Pearl = 4926@

The series given follow the pattern

+2, +2+4, +2+4+6, +2+4+6+8, +2+4+6+8+10,...

Here ? = 7 + 2 + 4 = 13.

The chemical name of the compound 

Cu2CO3 isCopper (i) carbonate and is also called as cuprous carbonate.

From the given statements A, B & C

Let the present age of Teja = P

Raju present age = P + 4

Sita's present age = 2(P + 4)

Average of ages of Sita & Teja = 19

=> (2P + 8 + P)/2 = 19

= 3P + 8 = 38

=> P = 30/3 = 10

Hence, the present age of Teja = P = 10 yrs.

Therefore, by using all the three statements A, B & C we can find the age of Teja.

Given the number series is 4, 6, 12, 30, 81, 315.

Here it follows a pattern that

4

4 x 1.5 = 6

6 x 2 = 12

12 x 2.5 = 30

30 x 3 = 90 not equals to 81

90 x 3.5 = 315

Hence the odd one in the series is 81.

In hydrocarbon, the boiling point directly varies with the length of carbon chain. On increasing the number of carbon atom, the boiling point of the compound also increases. Paraffin contains highest number of carbon atoms whereas, ethane is comprised of two carbon atoms.

The decreasing order of boiling point of mention compounds is written as follows:

Paraffin > Octadecane > Hexane > Neohexane > Ethane

The next number in the series is

143 143 136 110

      0    7      26 (Differences)

 $$\begin{gathered} 13 - 1 , 23 - 1, 33 - 1, 43 - 1,... \\ Now the next number is given by \\ 110 - (43 - 1) = 110 - 63 = 47. \end{gathered}$$