GATE Questions

Q:

Pen name of Rabindranath Tagore?

A) Bhanu Simha B) Gurudev
C) Kabiguru D) All of the above
 
Answer & Explanation Answer: D) All of the above

Explanation:

Pen names have had a certain place of their own in the world of writing. Pen names are something which every writer comes across at some time in their careers.

 

Indian author to use a pen name Bhanu Simha is Rabindranath Tagore. He also has Gurudev, Kabiguru as his pen names.

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Filed Under: Famous Personalities
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33 13283
Q:

In a parking lot there are two types of vehicles, two wheelers and four wheelers. The total number of the vehicles in the parking lot is 200. When the number of the wheels of all the vehicles is counted it is counted to be 580. Find the total number of the four wheeler vehicles in the parking lot ?

A) 110 B) 90
C) 100 D) 180
 
Answer & Explanation Answer: B) 90

Explanation:

Let number of 2 wheelers be 'x'
and 4 wheelers be 'y'

Given total number of vehicles = 200
i.e, x + y = 200 ....(1)

Given total number of wheels = 580
i.e, 2x + 4y = 580 ...(2)

By solving (1)&(2), we get

y = 90
=> x = 110

Therefore, number of two wheelers = 110
number of four wheelers = 90

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Filed Under: Arithmetical Reasoning
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21 13272
Q:

Which is the gas used for making vegetables and vanaspathi from vegetable oils?

A) Hydrogen B) Nitrogen
C) Argon D) Helium
 
Answer & Explanation Answer: A) Hydrogen

Explanation:

Hydrogen gas is used for making vegetables and vanaspathi from vegetable oils.

As it is colourless, odourless, tasteless, flammable gaseous substance, it is added to oils to make them more solid or spreadable.

The use of hydrogenation helps to prolong the shelf life of the food and maintain flavour stability.

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Filed Under: Chemistry
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25 13267
Q:

The marks obtained by Vijay and Amith are in the ratio 4:5 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of ?

A) 4:5 B) 6:5
C) 3:2 D) 1:3
 
Answer & Explanation Answer: B) 6:5

Explanation:

    4:5
    3:2
   -------
=> 12:15:10

 12:10

=> 6:5

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Filed Under: Ratios and Proportions
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11 13255
Q:

If a number 72k23l is divisible by 88. Then find value of k and l ?

A) k=8 & l=2 B) k=7 & l=2
C) k=8 & l=3 D) k=7 & l=1
 
Answer & Explanation Answer: B) k=7 & l=2

Explanation:

If a number to be divisile by 88, it should be divisible by both "8" and "11"

Check for '8' :
For a number to be divisible by "8", the last 3-digit should be divisible by "8"
Here 72x23y --> last 3-digit is '23y'
So y=2 [ (i.e) 232 is absolutely divisible by "8"]

Chech for '11' :
For a number to be divisible by "11" , sum of odd digits - sum of even digits should be divisible by "11"
(7 + x + 3) - (2 + 2 + y)
(7 + x + 3) - (2 + 2 + 2)
(10 + x) - 6 should be divisible by "11"
for x = 7
=> 17 - 6 = 11 [ which is absolutely divisible by "11"]

So x = 7 , y= 2.

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10 13230
Q:

In an exam, a candidate secured 504 marks out of the maximum mark of 'M'. If the maximum mark 'M' is converted into 800 marks, he would have secured 384 marks. What is the value of 'M' ?

A) 910 B) 1000
C) 970 D) None of the above
 
Answer & Explanation Answer: D) None of the above

Explanation:

504/M = 384/800

(504 x 800) / 384 = M

M = 1050

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13 13224
Q:

40% of 265 + 35% of 180 = 50% of ?

A) 383 B) 338
C) 84.5 D) 253.5
 
Answer & Explanation Answer: B) 338

Explanation:

We know that 40% = 25

 

40% of 265 + 35% of 180 = 50% ?

 

25 x 265 + 35% of 180 = 50% ?

 

We know that (35% of 180 = 180% of 35) & 180% = 95

 

25 x 265 + 95 x 35 = 50% ?

 

106 + 63 = 50% ?

 

?= 2 x 169 = 338.

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10 13214
Q:

At what time between 2 and 3 O'clock, the hands of a clock coincide ?

A) 1 10/11 minutes past 2 B) 1 10/11 minutes past 3
C) 1 11/10 minutes past 3 D) 11 10/11 minutes past 2
 
Answer & Explanation Answer: A) 1 10/11 minutes past 2

Explanation:

Since, in one hour, two hands of a clock coincide only once, so, there will be value.
Required time T = 211H×30 + Ao minutes past H.
Here H - initial position of hour hand = 2 (since 2 O'clock)
A° = Required angle = 0° (Since it coincides)

 

T = 2112×30 + 0o minutes past 2 

 

=> 11011 minutes past 2

 

 

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