GATE Questions

Q:

Mr. A, Miss B, Mr. C and Miss D are sitting around a table and discussing their trades.

1. Mr. A sits opposite to cook
2. Miss b sits right to the barber.
3. The washer man is on the left of the tailor
4. Miss D sits opposite Mr. C

What are the trades of A and B ?

A) Tailor and Barber B) Tailor and cook
C) Barber and cook D) washer man and cook
 
Answer & Explanation Answer: B) Tailor and cook

Explanation:

Clealry, C and D sit opposite to each other. So, if A sits opposite to cook, B shall be the cook.
Now, B is to the right of barber. So, one of the rest, say C will be barber.
Clealry, then D on the opposite side shall be washerman or tailor. But, washerman is left of tailor and D on the left of A.
So, D is washerman and A is tailor.

Thus, A and B are Tailor and Cook.

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17 17845
Q:

25 : 37 :: 49 : ?

A) 65 B) 69
C) 79 D) 81
 
Answer & Explanation Answer: A) 65

Explanation:

Here the given numbers are related in such a manner that,

52 = 255+12 + 1 = 37Similarly, 72 = 497+12 + 1 = 64 + 1 = 65

 

Hence, 25 : 37 :: 49 : 65.

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Filed Under: Analogy
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51 17797
Q:

NH3 oxidation number?

A) -1 B) +1
C) 0 D) -3
 
Answer & Explanation Answer: C) 0

Explanation:

NH3, Ammonia is a neutral compound as the individual oxidation numbers elements that make up the compound NH3 are Nitrogen (N) and Hydrogen (H) sum to zero. 

We do not speak of the oxidation number of a molecule. We can speak of the oxidation numbers of the individual elements that make up the compound.

 

Here the oxidation number of Nirogen is -3 and that of Hydrogen is +1.

Now, NH3 = 1(-3) + 3(+1) = -3 + 3 = 0.

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Filed Under: Chemistry
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31 17775
Q:

Milk and water are mixed in a vessel A as 4:1 and in vessel B as 3:2. For vessel C, if one takes equal quantities from A and B, find the ratio of milk to water in C.

A) 1:9 B) 9:1
C) 3:7 D) 7:3
 
Answer & Explanation Answer: D) 7:3

Explanation:

Ratio of Milk and water in a vessel A is 4 : 1

 

Ratio of Milk and water in a vessel B is 3 : 2

 

Ratio of only milk in vessel A = 4 : 5

 

Ratio of only milk in vessel B = 3 : 5

 

Let 'x' be the quantity of milk in vessel C

 

Now as equal quantities are taken out from both vessels A & B

 

=> 4/5     :     3/5
               x 
  3/5-x          x - 4/5

 

=> 35-xx-45 = 11 (equal quantities)

 

=> x = 7/10

 

Therefore, quantity of milk in vessel C  = 7

 

=> Water quantity = 10 - 7 = 3

 

Hence the ratio of milk & water in vessel 3 is 7 : 3 

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Filed Under: Alligation or Mixture
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33 17767
Q:

If the third day of a month is Tuesday, which of the following would be the 4th day before the 27th day of that month?

A) Tuesday B) Monday
C) Wednesday D) Sunday
 
Answer & Explanation Answer: B) Monday

Explanation:

Dates on which Tuesday fall are 3,10,17, and 24

 

Hence, the 27th day of the month will be (Tuesday + 3 days=)Friday

 

Required day of the month = Friday - 4 = Monday

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41 17766
Q:

In a test, minimum passing percentage for girls and boys is 35% and 40% respectively. A boy scored 483 marks and failed by 117 marks. What is the minimum passing marks for girls ?

A) 625 B) 525
C) 425 D) 325
 
Answer & Explanation Answer: B) 525

Explanation:

Given 40% minimum passing marks for boys = 483 + 117 = 600
=> 1% = 600/40
=> 100% = 600 x 100/40 = 1500
Minimum passing marks for girls = 35% of 1500 = 35 x 1500/100 = 525.

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Filed Under: Percentage
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15 17751
Q:

How many 6-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 and 7 so that the digits should not repeat and the second last digit is even ?

A) 521 B) 720
C) 420 D) 225
 
Answer & Explanation Answer: B) 720

Explanation:

Let last digit is 2
when second last digit is 4 remaining 4 digits can be filled in 120 ways, similarly second last digit is 6 remained 4 digits can be filled in 120 ways.
so for last digit = 2, total numbers=240

 

Similarly for 4 and 6
When last digit = 4, total no. of ways =240
and last digit = 6, total no. of ways =240
so total of 720 even numbers are possible.

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Filed Under: Permutations and Combinations
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14 17739
Q:

A merchant buys two articles for Rs.600. He sells one of them at a profit of 22% and the other at a loss of 8% and makes no profit or loss in the end. What is the selling price of the article that he sold at a loss ?

A) Rs. 404.80 B) Rs. 536.80
C) Rs.440 D) Rs. 160
 
Answer & Explanation Answer: A) Rs. 404.80

Explanation:

Let C1 be the cost price of the first article and C2 be the cost price of the second article.
Let the first article be sold at a profit of 22%, while the second one be sold at a loss of 8%.

We know, C1 + C2 = 600.
The first article was sold at a profit of 22%. Therefore, the selling price of the first article = C1 + (22/100)C1 = 1.22C1
The second article was sold at a loss of 8%. Therefore, the selling price of the second article = C2 - (8/100)C2 = 0.92C2.

The total selling price of the first and second article = 1.22C1 + 0.92C2.

As the merchant did not make any profit or loss in the entire transaction, his combined selling price of article 1 and 2 is the same as the cost price of article 1 and 2.

Therefore, 1.22C1 + 0.92C2 = C1+C2 = 600
As C1 + C2 = 600, C2 = 600 - C1. Substituting this in 1.22C1 + 0.92C2 = 600, we get
1.22C1 + 0.92(600 - C1) = 600
or 1.22C1 - 0.92C1 = 600 - 0.92*600
or 0.3C1 = 0.08*600 = 48
or C1 = 48/(0.3) = 160.
If C1 = 160, then C2 = 600 - 160 = 440.
The item that is sold at loss is article 2. The selling price of article 2 = 0.92*C2 = 0.92*440 = 404.80.

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Filed Under: Profit and Loss
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19 17712