GATE Questions

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Since Akhil has no brother or sister, so he is his father's only son.
So wife of Akhil's father's son---Akhil's wife.
Thus, Akhil's wife is the man's mother or the man is Akhil's son.

Among the given options, mud is not an aerosol.

An aerosol is a suspension of fine solid particles or liquid droplets, in the air or another gas. Aerosols can be natural or anthropogenic. Examples of natural aerosols are fog, dust, forest exudates and geyser steam. Examples of anthropogenic aerosols are haze, particulate air pollutants, and smoke.

NUMERICAL has 9 positions in which 2, 4, 6, 8 are even positions.

And it contains 5 consonents i.e, N, M, R, C & L. Hence this cannot be done as 5 letters cannot be placed in 4 positions.

Therefore, Can't be determined.

Duge Beipanjiang Bridge in southwest China, opened to traffic this week and now the highest bridge in the world, some 565 metres (1,854 feet) above the valley below.The bridge stretches across a 1,341-metre (4,400-foot) span. Three years in the making, it's estimated to have cost the Chinese government around 1 billion yuan (or US$144 million).The bridge is going to cut travel times between Liupanshui in the Guizhou province and Xuanwei in the Yunnan province to two hours instead of the current five – as long as you don't mind the heights.The bridge crosses the the Nizhu river, and to give you some idea of the size of the drop down to the water below, it's almost 2 Eiffel Towers or one-and-a-half Empire State Buildings.

Given that,

 working days = 5

 working hours = 8

 A man get rupess per hour is Rs.2.40

 So in one day the man get total rupees is 2.40 x 8 = 19.2

 So in 5 days week the man get total rupees is 19.2 x 5 = 96

 So in 4 week the man get total rupees is 96 x 4 = 384

 So the man worked for = 160hours in 4 weeks

 But given that the man earned Rs.432

 Hence remaning money is (432-384 = 48)which is earn by doing overtime work

Overtime hours  = 48/3.20 = 15

So total worked hours is = 15 + 160 = 175.

729 = 9 x 9 x 9

=> Cube root of 729 = 9

Now, required square of 9 = 9 x 9 = 81.

From the given information, the circular arrangement is

Here F is second to the right of B and the remaning all are wrong.

Let S be the sample space.
Here n(S)= 23 = 8
Let E be the event of getting atmost two heads. Then,
n(E) = {(H,T,T), (T,H,T), (T,T,H), (H,H,T), (T,H,H), (H,T,H)}
Required probability = n(E)/n(S) = 6/8 = 3/4.