GATE Questions

Q:

If a person having Rs. 2000 and he want to distribute this to his five children in the manner that each son having Rs. 30 more than the younger one , what will be the share of youngest child ?

A) Rs. 175 B) Rs. 325
C) Rs. 340 D) Rs. 260
 
Answer & Explanation Answer: C) Rs. 340

Explanation:

Assume first child (the youngest) get = Rs. x

According to the question ;
each son having Rs. 30 more than the younger one

Second child will get = Rs. x + 30
Third child will get = Rs. x + 30 + 30 = x + 60
Forth child will get = Rs. x + 30 + 30 + 30 = x + 90
Fifth child will get = Rs. x + 30 + 30 + 30 + 30 = x + 120

Total amount they got = Rs. 2000

x + (x+30) + (x+60) + (x+90) + (x+120) = 2000
5x + 300 = 2000
5x = 1700
x = Rs. 340
So the youngest child will get Rs. 340.

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Filed Under: Chain Rule
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22 5530
Q:

In a daily morning walk three persons step off together. their steps measure 75 cm, 80 cm and 85 cm respectively. What is the minimum distance each should walk so that thay can cover the distance in complete steps  ?

A) 222 m 44 cm B) 204 m
C) 201 m 21 cm D) 208 m
 
Answer & Explanation Answer: B) 204 m

Explanation:

To find the minimum distance, we have to get the LCM of 75, 80, 85

Now, LCM of 75, 80, 85 = 5 x 15 x 16 x 17 = 20400

Hence, the minimum distance each should walk so that thay can cover the distance in complete steps = 20400 cms = 20400/100 = 204 mts.

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Filed Under: Time and Distance
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11 5528
Q:

Which ionization process requires the most energy?

A) C3+ (g) → C4+ (g) + e- B) C (g) → C+ (g) + e-
C) C2+ (g) → C3+ (g) + e- D) C+ (g) → C2+ (g) + e-
 
Answer & Explanation Answer: A) C3+ (g) → C4+ (g) + e-

Explanation:

We know that each successive IE is greater than the previous one, because each ionization process removes one electron and hence increases the total attractive force on the remaining electrons from the nucleus. Hence, C3+ (g) → C4+ (g) + e- needs more energy.

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Filed Under: Chemistry
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1 5522
Q:

A Conical tent was erected by the army at a base camp with height 3 m and base diameter 10 m. If every person requires 3.92 cu.m air, then how many persons can be seated in that tent approximately?

A) 20 B) 19
C) 17 D) 22
 
Answer & Explanation Answer: A) 20

Explanation:

Given height of the conical tent = 3 m

Diameter = 10 => Radius = D/2 = 10/2 = 5 m 

Now, as the tent is in the conical form

Volume of the conical tent = πr2h3 

=> (22 x 5 x 5 x 3) / (7 x 3) 

= 22 x 25/7 

= 78.54 cu.m 

Given each person requires 3.92 cu.m of air 

=> Number of persons can be seated in the tent = 78.54/3.92 = 20.03 =~ 20

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Filed Under: Volume and Surface Area
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17 5520
Q:

If the average height of boys in a hall is 180 cm and that of girls is 150 cm. If the average height of the gathering is 165 cm, then find the number of girls present in the hall if the number of boys present in the hall are 78 ?

A) 56 B) 64
C) 87 D) 78
 
Answer & Explanation Answer: D) 78

Explanation:

Using Trial and error method,

we get the number of girls in the hall = 78

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27 5515
Q:

If a girl cycles at 10 kmph, then she arrives at a certain place at 1 p.m. If she cycles at 15 kmph, she will arrive at the same place at 11 a.m. At what speed must she cycle to get there at noon?

A) 14 kmph B) 13 kmph
C) 12 kmph D) 11 kmph
 
Answer & Explanation Answer: C) 12 kmph

Explanation:

The distance is constant in this case.

Let the time taken for travel with a speed of 10 kmph be 't'.

Now the speed of 15 kmph is 3/2 times the speed of 10 kmph.

Therefore, time taken with the speed of 15 kmph will be 2t/3 (speed is inversely proportional to time)

Extra time taken = t - 2t/3 = t/3

=> 1pm - 11am = 2hrs

=> t/3 = 2h

=> t = 6 hrs.

Now, Distance = speed x time = 10 x 6 = 60 kms

Time he takes to reach at noon = 6 - 1 = 5 hrs

Now, Speed = 60/5 = 12 kmph.

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12 5508
Q:

Sneha’s weight is 140% of Veena’s weight. Rina’s weight is 90% of Sana’s weight. Sana weighs twice as much as Veena. If Sneha’s weight is x% of Rina’s weight, then x is equal to:

A) 596/9 B) 605/9
C) 645/9 D) 700/9
 
Answer & Explanation Answer: D) 700/9

Explanation:

Let Veena's weight = 1 kg

Sana's weight = 2 kg

Sneha's weight = 1.4 kg

Rina's weight = 1.8 kg

Now,according to the given data in the question,

1.8x100 = 1.4

 

x = 1.4 × 1001.8 = 7009 = 77 79.

 

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8 5508
Q:

K is 4 times as fast as L and working together, they can complete a work in 24 days. In how many days can L alone complete the work ?

A) 30 days B) 40 days
C) 120 days D) 80 days
 
Answer & Explanation Answer: A) 30 days

Explanation:

Given K=4L 

-->K+L = 4L+L = 5L

 

These 5L people can complete the work in 24 days, which means L alone can do the work in (24 x 5)=120 days.

 

Hence, K alone can do the work in 120/4= 30 days.

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Filed Under: Time and Work
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4 5507