GATE Questions

Q:

Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it?

 ___ utt ___ tt ___ ttu ___   

A) t t u t B) t u t t
C) t u u t D) t t t u
 
Answer & Explanation Answer: C) t u u t

Explanation:

t, u, u and t.

The sequence is : tut tut tut tut.

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Filed Under: Alphabet Test
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Q:

The reactivity of an atom arises from 

A) the existence of unpaired electrons in the valence shell B) the energy differences between the electron shells
C) the sum of the potential energies of all the electron shells D) the average distance of the outermost electron shell from the nucleus
 
Answer & Explanation Answer: A) the existence of unpaired electrons in the valence shell

Explanation:

When atoms react they do so in order to reach the lowest energy, which is the most stable. The electrons orbitals will overlap in the way that reduces the energy the most. Orbitals of similar energy will produce the greatest stabilisation.The answer you gave isn't the whole story, it depends what species is reacting with what. The effective nuclear charge on the atom will affect the energy of the valance electrons.

 

Hence, the reactivity of an atom arises from the existence of unpaired electrons in the valence shell.

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Filed Under: Chemistry
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4 6709
Q:

Poison glands of snakes are homologous to

A) sebaceous glands of mammals B) salivary glands of vertebrates
C) stings of rays D) electric organs of fishes
 
Answer & Explanation Answer: B) salivary glands of vertebrates

Explanation:

Here Homologous Means having the same relation or relative position or structure. 

Here in snakes poison is in glands and here salivary glands are in Vertebrates.

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Filed Under: Biology
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Q:

Order of basicity of amines in gaseous state?

A) 2'> 1'> 3' > NH3 B) 3' > 2' > 1'> NH3
C) 1' > 2' > 3'> NH3 D) 2'> 3'> 1' > NH3
 
Answer & Explanation Answer: B) 3' > 2' > 1'> NH3

Explanation:

The order of basicity in ammonia is different in gaseous phases vs. aqueous phases due to hydrogen bonding.

 

So in gaseous phases it's the well known: 3' > 2' > 1'> NH3. Just so we're on the same page, this is due to the inductive effect of electron donating alkyl groups--they destabilize the lone pair on nitrogen atom, making nitrogen more basic.

 

But in aqueous phase, the order is slightly different: 2'> 1'> 3' > NH3.

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Filed Under: Chemistry
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Q:

The compound interest earned by Sunil on a certain amount at the end of two years at the rate of 8% p.a. was Rs.2828.80. Find the total amount that Sunil got back at the end of two years in the form of principal plus interest earned  ?

A) Rs. 11828.80 B) Rs. 19828.80
C) Rs. 9828.80 D) Rs. 19328.80
 
Answer & Explanation Answer: B) Rs. 19828.80

Explanation:

Let the sum be Rs. P
P{ 1+81002- 1 } = 2828.80

 

It is in the form of  a2-b2 = a+ba-b

 

P(8/100)(2 + 8/100) = 2828.80

 

P = 2828.80 / (0.08)(2.08)

 

= 1360/0.08 = 17000

 

Principal + Interest = Rs. 19828.80

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Filed Under: Compound Interest
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Q:

Indicating to a photo, Mukesh said that this Man’s son is my father’s son. Who was there in the photo ?

A) Mukesh Uncle B) Mukesh Brother
C) Mukesh Grandfather D) Mukesh Father
 
Answer & Explanation Answer: D) Mukesh Father

Explanation:

That man's son means Mukesh

=> Mukesh father's son is Mukesh

=> It is Mukesh's father.

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Filed Under: Blood Relations
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43 6687
Q:

An alloy of copper and bronze weight 50g. It contains 80% Copper. How much copper should be added to the alloy so that percentage of copper is increased to 90%?

A) 45 gm B) 50 gm
C) 55 gm D) 60 gm
 
Answer & Explanation Answer: B) 50 gm

Explanation:

Initial quantity of copper =80100 x 50 = 40 g 

And that of Bronze = 50 - 40 = 10 g

Let 'p' gm of copper is added to the mixture

=> 50 + p x 90100 = 40 + p

=> 45 + 0.9p = 40 + p

=> p = 50 g

Hence, 50 gms of copper is added to the mixture, so that the copper is increased to 90%.

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Filed Under: Alligation or Mixture
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20 6686
Q:

A Product is supported each week by the same three Product supporters. Last month the first supporter took 440 calls, the second took 360 calls, and the third took 300 calls. This month the job will consists of 1500 calls. If the three supporters each increase their work proportionately, how many more calls will the second supporter take this month than last month ?

A) 131 calls B) 160 calls
C) 491 calls D) 600 calls
 
Answer & Explanation Answer: A) 131 calls

Explanation:

1st supporter recieve 440 calls
2nd supporter recieve 360 calls
3rd supporter recieve 300 calls

So total calls = 1100 calls ;
Calls this month= 1500
So remaining calls to be distributed is 400

So Now Ratio 1st:2nd:3rd ==> 440:360:300
=> 22:18:15

Now No. of More Calls 2nd supporter will get => [18/(22+18+15)] x 400
=> (18/55) x 400
=> 131 Calls
So 131 more Calls than last month.

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Filed Under: Ratios and Proportions
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