GATE Questions

---

We will rewrite the formula as an equation.

2K + 2Cr + 7O = 0

The zero comes from there being no overall charge on the compound.

Each oxidation number is represented by the element's symbol.

Since this compound is not a peroxide or superoxide, the oxidation value for O is -2

K being in group 1 has a +1 charge and therefore has an oxidation number of K is +1

Now, by putting known values in we have:

2(+1) + 2(Cr) + 7(-2) = 0

2 + 2Cr -14 = 0

2Cr = +12

Cr = +6.

That which cannot be conquered is called as Invincible.

One who speaks less is called as Reticent.

A pardonable offence is called as Venial.

6,400 gents, 2400 ladies in that company.
So total 8,800employees.
for 8,800 employees, we want 2400 ladies.
for 12,100employees we want how many ladies ?
=> (12,100/8,800) x 2400 = 3300.
So we want 3300 - 2400 = 900 more ladies.

The rule followed here is

7 + 3 - 4 = 6

Similarly,

4 + 2 - 2 = 4

9 + 5 - 4 = 10

Hence, the missing numbers are 4 & 10.

Ratio of investment of all the three members = (7 x 12) : (9 x 12) : (2/3 x 9 x 6)

= 7 : 9 : 3

Given Rushi's one year profit = Rs. 5600

=> Let the total profit = Rs. P

Then,

P x 7/19 = 5600

Total profit P = 19 x 5600/7 = Rs. 15,200.

100
65
-------
65 ------- 35
100 ------ ? => 53.84 %

From the given information the arrangement can be done as follows:

 Position  Box  Colour

      7         C       Blue
      6         F       Green
      5         B       Purple
      4         E       Orange
      3         G       Pink
      2         A       Red
      1         D       Yellow

The stability of the ions is determined by the energy of the lone pairs. Carbon has the least effective nuclear charge (Zeff) and so the lone pair on the CH3− ion has the highest energy, making it the least stable ion and so the strongest base. The Zeff increases as we move across the period until we get to fluorine which has the greatest Zeff and so its lone pairs have the lowest energy, making F− the least basic ion.

In order of decreasing basicity they are ranked LiCH3 > LiNH2 > LiOH > LiF. We are dealing with the ions F−, OH−, NH2− and CH3− and so the factor which influences their basicity is the stability of the ion compared to its conjugate acid.