GATE Questions

Q:

What is needed for steering control on a PWC?

Answer

PWC refers to Personal Water Crafts.


To control steering on a PWC, the most needed requirement is to have power in which will allows the one using it to control the engine for it to stop or for it to move. Without power, the person using it could be out of balance or fail to start the engine. This is the basic requirement because even though it is shut off or the engine is off, the PWC is still on and it could still move without proper knowledge of the engine.

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Subject: Physics Exam Prep: AIEEE , Bank Exams , CAT , GATE
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3 10525
Q:

Arun and Varun started business in partnership investing Rs. 20,000 and Rs. 15,000 respectively. After six months, Akhil joined them with Rs. 20,000. What will be Varun's share in the total profit of Rs. 25,000 earned at the end of 2 years from the starting of the business ?

A) Rs. 7500 B) Rs. 4520
C) Rs. 8750 D) Rs. 6350
 
Answer & Explanation Answer: A) Rs. 7500

Explanation:

Arun : Varun : Akhil = (20000 x 24) : (15000 x 24) : (20000 x 18) = 4:3:3

B's share = 25000 x 3/10 = Rs. 7500.

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Filed Under: Partnership
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5 10523
Q:

There is 50% increase in an amount in 5 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate ?

A) Rs. 5422 B) Rs. 5489
C) Rs. 3972 D) Rs. 6145
 
Answer & Explanation Answer: C) Rs. 3972

Explanation:

Let p = Rs. 100.

Then, S.I is Rs. 50 and time = 5 years. 

 R = 100×50100×5= 10% p.a.

 

Now, p = Rs. 12,000 , T = 3 years and R = 10% p.a.


C.I. = Rs. 12000×1+101003-1= Rs. 3972

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Filed Under: Compound Interest
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
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7 10516
Q:

H.C.F of 4 x 27 x 3125, 8 x 9 x 25 x 7 and 16 x 81 x 5 x 11 x 49 is :

A) 360 B) 180
C) 90 D) 120
 
Answer & Explanation Answer: B) 180

Explanation:

4 x 27 x 3125 = 22 × 33 × 55 ;

 

8 x 9 x 25 x 7 = 23 × 32 × 52 × 7

 

16 x 81 x 5 x 11 x 49 = 24 × 34 × 5 × 11 × 72

 

H.C.F = 22 × 32 × 5 = 180.

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Filed Under: HCF and LCM
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23 10506
Q:

In how many ways can 100 soldiers be divided into 4 squads of 10, 20, 30, 40 respectively?

A) 1700 B) 18!
C) 190 D) None of these
 
Answer & Explanation Answer: D) None of these

Explanation:

100C10 + 90C20 + 70C30 + 40C40 = 100!10!x20!x30!x40!

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Filed Under: Permutations and Combinations
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4 10497
Q:

Three maths classes: A, B and C take an algebra test. The average score of class A is 83. The average score of class B is 76. The average score of class C is 85. The average score of class A and B is 79 and average score of class B and C is 81. What is the average score of classes A, B, C ?

A) 81 B) 78
C) 80.5 D) 81.5
 
Answer & Explanation Answer: D) 81.5

Explanation:

Let the number of students in classes A, B and C be P, Q and R respectively.
Then, total score of A = 83P, total score of B = 76Q, total score of C = 85R.
Also given that,
(83P + 76Q) / (P + Q) = 79
=>4P = 3Q.
(76Q + 85R)/(Q + R) = 81
=>4R = 5Q,
=>Q = 4P/3 and R = 5P/3
Therefore, average score of A, B, C = ( 83P + 76Q + 85R ) / (P + Q + R) = 978/12 = 81.5

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Filed Under: Average
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12 10468
Q:

Sony is one-fifth the age of her mother 15 years ago and Sony’s brother is three-fifth the age of his mother 10 years ago. If the sum of Sony and her brother’s ages is 31 then how old is Sony's mother ? 

A) 40 B) 50
C) 60 D) 70
 
Answer & Explanation Answer: B) 50

Explanation:

Sony and her brother's age sum is 31
Let Sony's mother's age be 'x'.
Now the conditions given for both of their ages related to their mom is
1/5(x-15) + 3/5(x-10) = 31
x-15 + 3x-30 = 155
4x-45 = 155
4x = 200
x = 50
So, Mother's age = 50.

Cross verification : 15 years ago age = 35 => Sony age = 7
10 years ago age = 40 => bro age = 24

Sum = 24 + 7 = 31.

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Filed Under: Problems on Ages
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9 10452
Q:

What holds the sides of the DNA ladder together?

A) Polar covalent bonds B) Ionic bonds
C) Metallic bonds D) Covalent bonds
 
Answer & Explanation Answer: D) Covalent bonds

Explanation:

Deoxyribose, which is a pentose, and a phosphate group are the two molecules together form the two sides of the DNA i.e, A sugar (deoxyribose) and a phosphate.

DNA is a double-stranded molecule twisted into a helix (think of a spiral staircase). Each spiraling strand, comprised of a sugar-phosphate backbone and attached bases, is connected to a complementary strand by non-covalent hydrogen bonding between paired bases. The bases are adenine (A), thymine (T), cytosine (C) and guanine (G). A and T are connected by two hydrogen bonds. G and C are connected by three hydrogen bonds.

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Filed Under: Biology
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16 10441