GATE Questions

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ARC -> CRA ->(+1) DSB
    H ->     H ->(-1) G
IVE  ->  EVI ->(+1) FWJ

 Similarly,

 SYS -> SYS ->(+1) TZT
    T ->     T ->(-1) S
EMS -> SME ->(+1) TNF

Given total number of passengers in the bus = 45

First average weight of 45 passengers = 52 kgs

Average weight of 5 passengers who leave bus = 48

Average weight of 5 passengers who joined the bus = 54

Therefore, the net average weight of the bus is given by

$$\begin{gathered} = 45 x 52 - 5 x 48 + 5 x 5445 \\ = 237045 \\ = 1583 \\ = 52.66 kgs. \end{gathered}$$

Given 45 kg for painting 

And 6% 0f 45 for wasting => 6x45/100 = 2.7 kg

Now total paint required = 45+2.7 = 47.7 kgs

But tins are available in only 4kgs

Then, no. of tins req = 47.7/4 = 11.4 => 12 tins

Given k : l = 4 : 3
l : m = 5 : 3

Then k : l : m = 20 : 15 : 9

C.I = P1+r100t-1

594.5 = 58001+r1002-1

 594.55800+1=1+r1002

r100=1.05-1=0.05=> r = 5 % .

Here 5, 7 & 9 are repeating after modulation.

Let wholesaler dealers marked price = 100%, Retailer's C.P = 80%
And the retailer sells at 5% less than the marked price => S.P = 95%
If S.P of 95% of the retailer costs Rs.19 to customer,so its C.P of 80% will cost 80 x 19/95 = 16
Profit made by the retailer = 19-16 =  Rs.3

2nd Jan 1901 means
(1900 years and 2 day)
Now, 1600 years have 0 odd day
300 years have 1 odd day
2 days has 2 odd day
Total no. of odd days = 0 + 1 + 2 = 3 days
Hence, the day on 2nd Jan 1901 was Wednesday.