AIEEE Questions

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The gram formula mass is nothing but molar mass.

Composition :

Symbol      Element       Atomic weight       Atoms
   

     P         Phosphorus       30.973762               1       = 30.973
   

     O         Oxygen             15.9994                  4       =  63.998
   

     N         Nitrogen            14.0067                  3       =  42.020
   

     H         Hydrogen          1.00794                  12      =  12.096

Total   =  30.973+63.998+42.020+12.096 = 149.087

Desertification is a type of land degradation in which a relatively dry area of land becomes increasingly arid, typically losing its bodies of water as well as vegetation and wildlife.

Conversion of a grassland or an already arid land into a desert through indiscriminate human actions magnified by droughts.

Hence, forest improving to deserts is refers to desertification.

The sciatic nerve is a combination of common fibular and tibial. 

The sciatic nerve divides into its two branches::

1. The tibial nerve

2. The common fibular nerve

at the popliteal fossa.

The tibial nerve, which travels down the posterior compartment of the leg into the foot.

The common peroneal nerve also called the common fibular nerve, which travels down the anterior and lateral compartments of the leg into the foot.

Materials that allow electricity to flow are called electrical conductors and that materials which does not allow electricity to flow are called Insulators.

By trial and error method,

P=0, Q=9, R=0 satisfies the values.

Let R, G and B represent the number of balls in red, green and blue boxes respectively.

Then, .

R + G + B = 108 ...(i),

G + R = 2B ...(ii)

B = 2R ...(iii)

From (ii) and (iii), we have G + R = 2x 2R = 4R or G = 3R.

Putting G = 3R and B = 2R in (i), we get:

R + 3R + 2R = 108 6R = 108 R = 18.

Therefore Number of balls in green box = G = 3R = (3 x 18) = 54.

The gram formula mass of a compound is nothing but the molar mass.

The molar mass of K2CO3 (Potassium Carbonate) is given by

Atomic weights of individual elements are

K (Potassium) = 39 g

C (Carbon) = 12 g

O (Oxygen) = 16 g

Hence, that of K2CO3 = 39(2) + 12 + 16(3)

= 78 + 12 + 48

= 138.