AIEEE Questions

Q:

If a carrier wave of 1000 kHz is used to carry the signal, the length of transmitting antenna will be equal to _____ ?

A) 300 m B) 30 m
C) 3 m D) 0.3 m
 
Answer & Explanation Answer: A) 300 m

Explanation:

h =  straight c over straight v = 3 × 108/106 = 300 m

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Q:

Two solutions have milk & water in the ratio 7:5 and 6:11. Find the proportion in which these two solutions should Be mixed so that the resulting solution has 1 part milk and 2 parts water ?

A) 7 : 12 B) 8 : 13
C) 9 : 4 D) 2 : 5
 
Answer & Explanation Answer: B) 8 : 13

Explanation:

To get the solution that contains 1 part of milk and two parts of water,
they must be mixed in the ratio as
7x+6x/5y+11y = 1/2
26x = 16y
x/y = 16/26
x/y = 8/13

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Filed Under: Ratios and Proportions
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Q:

Find the logarithm of 144 to the base 23 :

A) 2 B) 4
C) 8 D) None of these
 
Answer & Explanation Answer: B) 4

Explanation:

log23144 = 4 

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Filed Under: Logarithms
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Q:

38% of 7500 +  ?% of 375 = 50% of 6000

A) 50 B) 40
C) 60 D) 45
 
Answer & Explanation Answer: B) 40

Explanation:

Let ? = p

38 x 7500/100  + p x 375/100 = 50 x 6000/100

=> 38 x 75 + 3.75p = 3000

=> 3.75p = 3000 - 2850

=> p = 150/3.75 

=> p = ? = 40

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Filed Under: Simplification
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Q:

ITC sells one product at a profit of 20% another at a loss of 20% at the same selling price. What is the loss incurred by ITC?

A) 1% B) 2%
C) 4% D) 0%
 
Answer & Explanation Answer: C) 4%

Explanation:

loss % = common gain or loss102 %

 

           = (20/10)x(20/10)% = 4%

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Filed Under: Profit and Loss
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Q:

Alpha is to Omega as First is to what?

A) Last B) Beta
C) Gamma D) End
 
Answer & Explanation Answer: A) Last

Explanation:

We know that, ALpha and Omega are the first and last lettrs of in the Greek alphabet. Hence, alpha is to omega as first is to last.

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Filed Under: Alphabet Test
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Q:

The primary tool used in structured design is a

A) module B) structure chart
C) program flowchart D) data-flow diagram
 
Answer & Explanation Answer: B) structure chart

Explanation:

The primary tool used in structured design is a structure chart.

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Q:

A potentiometer wire is 100 cm long and a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obtained at 50 cm and 10 cm from the positive end of the wire in the two cases. The ratio of the emf's is :

A) 3:4 B) 5:4
C) 5:1 D) 3:2
 
Answer & Explanation Answer: D) 3:2

Explanation:

In series : E1 + E2 = K(50)

In parallel : E1 - E2 = K(10)

E1 + E2 / E1 - E2 = 5/1

=> E1/E2 = 3/2

The emf's are in the ratio of 3:2.

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Filed Under: Physics
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