CAT Questions

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Given X can do in 10 days 

=> 1 day work of X = 1/10

Y can do in 15 days 

=> 1 day work of Y = 1/15

1day work of (X + Y) = 1/10 + 1/15 = 1/6

Given they are hired for 5 days

 => 5 days work of (X + Y) = 5 x 1/6 = 5/6

 Therefore, Unfinished work = 1 - 5/6 = 1/6 

55 min. spaces are covered in 60 min.

60 min. spaces are covered in min. = min.

Loss in 64 min. = min.

Loss in 24 hrs = min. = min.

Abiotic and biotic factors are what make up an ecosystem.

Abiotic factors are all nonliving components of an ecosystem. These factors include chemical and geological features such as water or lack of water, soil, rocks, and minerals. Other abiotic factors include physical components such as the temperature and weather affecting the ecosystem.


The biotic factors in an ecosystem include all living things. All plants, animals, fungi, protists, and bacteria within an ecosystem make up that system's biotic factors. The biotic factors can be broken down further into producers, consumers, and decomposers.

The biotic factors present in an ecosystem are highly dependent on the abiotic factors that are present. Even slight changes to either factor can have a major consequence upon the system as a whole.

Major fructose sources include all fruits and honey.

Days in 4 years => 

Let the first year is Normal year i.e, its not Leap year. A Leap Years occurs once for every 4 years.

4 years => 365 + 365 + 365 + 366(Leap year)

4 years => 730 + 731 = 1461

Therefore, Number of Days in 4 Years = 1461 Days.

R is the sister of U

Let work done by 1 man in i day be m

and Let work done by 1 boy in 1 day be b

From the given data,

4(5m + 3b) = 23

20m + 12b = 23....(1)

2(3m + 2b) = 7

6m + 4b = 7 ....(2)

By solving (1) & (2), we get

m = 1, b = 1/4

Let the number of required boys = n

6(7 1 + n x 1/4) = 45

=> n = 2.

work done=total number of person x number of days;
half of work done = 140 x 66;
For half of remaining work 25 extra men are added.
Therefore, total men for half work remaining = 140 + 25 = 165;
Let 2nd half work will be completed in K days;
140 x 66 = 165 x K
K = 122;
Hence, extra days => 122-120 = 2days.