CAT Questions

Q:

Refer the below data table and answer the following question.

If the imports in 2012 was Rs. 700 crores and the total exports in the years 2012 and 2013 together was Rs. 4000 crores, then the imports in 2013 was ?

A) 3888 B) 3222
C) 778 D) 2500
 
Answer & Explanation Answer: B) 3222

Explanation:
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Filed Under: Table Charts
Exam Prep: CAT , Bank Exams

1 9251
Q:

Excretion is best described as the removal of

A) Undigested material from the digestive tract B) Metabolic wastes from a cell
C) Toxic wastes by the process of cyclosis D) Water molecules from dipeptide hydrolysis
 
Answer & Explanation Answer: B) Metabolic wastes from a cell

Explanation:

Excretion is best described as the removal of Metabolic wastes from a cell.

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Filed Under: Biology
Exam Prep: AIEEE , Bank Exams , CAT
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21 9249
Q:

A boat travels 72 km downstream in 8 hours and 84 km upstream in 12 hours. Find the speed of the boat in still water and the speed of the water current ?

A) 9 and 3 kmph B) 6 and 7 kmph
C) 8 and 1 kmph D) 7 and 2 kmph
 
Answer & Explanation Answer: C) 8 and 1 kmph

Explanation:

Downstream speed = 72km/8hrs  = 9 kmph
upstream speed = 84km/12hrs = 7 kmph
speed of boat = avg of downstream and upstream speeds
speed of boat = (9+7)/2kmph = 8 kmph.
current speed = half of the difference of downstream and upstream speeds
currend speed = (9-7)/2kmph = 1 kmph

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Filed Under: Boats and Streams
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19 9247
Q:

Find the principal if the interest compounded at the rate of 10% per annum for two years is Rs. 420 ?

A) Rs. 2000 B) Rs. 2100
C) Rs. 1900 D) Rs. 2150
 
Answer & Explanation Answer: A) Rs. 2000

Explanation:

Given,
Compound rate, R = 10% per annum
Time = 2 years
C.I = Rs. 420
Let P be the required principal.
A = (P+C.I)
Amount, A = P1 + r100n

(P+C.I) = P1 + 101002

(P+420) = P[11/10][11/10]

P-1.21P = -420

0.21P = 420

Hence, P = 420/0.21 = Rs. 2000

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Filed Under: Compound Interest
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7 9244
Q:

A person is asked to put in a basket one apple when ordered 'one', one guava when ordered 'two', one orange whe ordered 'three' and is asked to take out from the basket one apple and one guava both when ordered 'four'. The ordered sequence executed by the person is as follows :

1 2 3 3 2 1 4 2 3 1 4 2 2 3 3 1 4 1 1 3 2 3 4


1. How many apples will be there in the basket at the end of the above order sequence ?
      (a) 4     (b) 3     (c) 2    (d) 1


2. How many fruits will be there in the basket at the end of the above order sequence ?
      (a) 13   (b) 17   (c) 9    (d) 11

Answer

1. Answer (c)


Each time we order 1, one apple is added to the basket but each time when 4 is ordered, one apple is removed from it.


Required number of apples = number of 1's - number of 4's = 6 - 4 = 2


2. Answer (d)


Each time we order 1, 2 or 3, one fruit is added to the basket but when ever we order 4, two fruits are removed from it.


Required number = Number of 1's + Number of 2's + Number of 3's - 2 x (Number of 4's)


= 6 + 6 + 7 - (2x4)
= 19 - 8
= 11.

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13 9239
Q:

Four persons can cross a bridge in 3,7,13,17 minutes.Only two can cross at a time.Find the minimum time taken by the four to cross the bridge ?

A) 17 minutes B) 20 minutes
C) 34 minutes D) 12 minutes
 
Answer & Explanation Answer: B) 20 minutes

Explanation:

First send 17 and 7. After 7 minutes, 7 is at finish and 17 needs 10 more minutes to complete his travel. now send 13. After 10 minutes 17 reaches finish and 13 needs 3 more minutes to complete. now send 3. both 3 and 13 reach destination at the same time after 3 minutes. hence the time taken is 7+10+3=20 minutes.

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Filed Under: Logic
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15 9236
Q:

An Engine length 1000 m moving at 10 m/s. A bird is flying from engine to end with 'x' m/s and coming back at '2x' m/s. Take total time of bird travelling as 187.5 s. Find x and 2x in km/hr ?

A) 21.4 and 42.8 B) 25.2 and 50.4
C) 31.4208 and 62.8416 D) 33.12 and 66.24
 
Answer & Explanation Answer: C) 31.4208 and 62.8416

Explanation:

Birds speeds in mtrs/sec is 'x' and '2x' .
While flying from Engine to end, relative speed = (x+10) m/sec
from end to engine, flying speed = (2x - 10) mtr/sec
so
1000/(x+10) + 1000/(2x-10) = 187.5 secs
solving it, we get
so x = 8.728 m/sec and 2x= 17.456 m/sec

x = 31.4208 km/hr and 2x = 62.8416 km/hr.

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Filed Under: Problems on Trains
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11 9234
Q:

In how many years, Rs. 200 will produce the same interest @ 5 % as Rs. 900 produce in 2 years @ 3 ½ %  ?

A) 5.2 yrs B) 7 yrs
C) 7.9 yrs D) 6.3 yrs
 
Answer & Explanation Answer: D) 6.3 yrs

Explanation:

P = Rs. 900, R = 3 ½ % = 7/2 %, T = 2 years. 

Therefore, 

S.I. = PTR/100

S.I. = Rs. (900 x 7/2 x 2/100) = Rs. 63

Now, P = Rs. 200, S.I. = Rs. 63, R = 5 %

Time = ((100 x 63) / (200 x 5) ) years = 6.3 years.

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Filed Under: Simple Interest
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6 9230