CAT Questions

Q:

Find the greatest number that will divide 964, 1238 and 1400 leaving remainder of 41,31 and 51 respectively ?

A) 64 B) 69
C) 71 D) 58
 
Answer & Explanation Answer: C) 71

Explanation:

To find the greatest number which divides the numbers 964, 1238 and 1400 leaving the remainders 41, 31 and 51 is nothing but the HCF of (964 - 41), (1238 - 31), (1400 - 51).

Therefore, HCF of 923, 1207 and 1349 is 71.

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Filed Under: HCF and LCM
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20 14612
Q:

How is my father's brother's only sibling's mother related to my sister's only brother ?

A) Neice B) Aunt
C) Mother D) Grand-mother
 
Answer & Explanation Answer: D) Grand-mother

Explanation:

My father's brother's only sibling is my father. My father's mother is my grandmother. My sister's only brother is myself. So she is my Grandmother.

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Filed Under: Blood Relations
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15 14609
Q:

Peacock : India :: Bear : ?

A) England B) America
C) Russia D) Africa
 
Answer & Explanation Answer: C) Russia

Explanation:

Here the relation between the given words is that the first word is the National animal of the second word.

As Peacock is the national bird of India, similarly Bear is the national animal of Russia.

 

Hence, Peacock : India :: Bear : Russia.

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Filed Under: Analogy
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19 14575
Q:

5/9 of the part of the population in a village are females. If 30 % of the females are married. The percentage of unmarried males in the total males is ?

A) 62.5 % B) 125 %
C) 84.32 % D) 46.87 %
 
Answer & Explanation Answer: A) 62.5 %

Explanation:

Let total population = p
number of females = 5p/9
number of males =(p-5p/9) = 4p/9
married females = 30% of 5p/9 = 30x5p/100x9 = p/6
married males = p/6
unmarried males =(4p/9-p/6) = 5p/18
Percentage of unmarried males in the total males = {(5p/18)/4p/9}x100 = (5p/18)x(9/4p) = 125/2 % = 62.5%

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Filed Under: Percentage
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21 14572
Q:

How is my father's mother's only daughter-in-law's daughter's father related to me ?

A) Son-in-law B) Uncle
C) Son D) Father
 
Answer & Explanation Answer: D) Father

Explanation:

My fahter's mother's only daughter-in-law is my father's wife i.e. my mother. My mother's daughter is my sister. My sister's father is my father.

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Filed Under: Blood Relations
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21 14533
Q:

6 men can complete a piece of work in 12 days. 8 women can complete the same piece of work in 18 days whereas 18 children can complete the piece of work in 10 days. 4 men, 12 women and 20 children work together for 2 days. If only men were to complete the remaining work in 1 day how many men would be required totally?

A) 38 B) 72
C) 36 D) 76
 
Answer & Explanation Answer: C) 36

Explanation:

Given 4men, 12 women and 20 children work for  2 days.

Workdone for 2 days by 4men, 12 women and 20 children = 4 x 26 x 12 + 12 x 28 x 18 + 20 x 218 x 10 = 12

Therefore, remaining work = 1 - 12 = 12

To complete the same work by only men in 1 day,

We know that M1 x D1 = M2 x D2

Here M1 = 6 , D1 = 12 and M2 = M , D2 = 1

12 x 6 = M x 1

=> M = 12 x 6 = 72

=> But the remaining work = 1/2

Men required => 1/2 x 72 = 36

Only men required to Complete the remaining work in 1 day = 36.

 

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Filed Under: Time and Work
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20 14507
Q:

The milk and water in two vessels A and B are in the ratio 4:3 and 2:3 respectively. In what ratio the liquids in both the vessels be mixed to obtain a new mixture in vessel c consisting half milk and half water?

A) 8:3 B) 6:7
C) 7:5 D) 11:7
 
Answer & Explanation Answer: C) 7:5

Explanation:

Milk in 1-litre mixture of A = 4/7 litre. 

Milk in 1-litre mixture of B = 2/5 litre. 

Milk in 1-litre mixture of C = 1/2 litre.

 

By rule of alligation we have required ratio X:Y   

   X                  :                 Y  

  4/7                                2/5  

           \                      /

              (Mean ratio)
                   (1/2) 

           /                      \

 (1/2 – 2/5)     :       (4/7 – 1/2)  

    1/10                      1/1 4 

 

So Required ratio = X : Y = 1/10 : 1/14 = 7:5

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Filed Under: Alligation or Mixture
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24 14465
Q:

A garrison of 2000 men has provisions for 54 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement ?

A) 1900 B) 2100
C) 1700 D) 2000
 
Answer & Explanation Answer: A) 1900

Explanation:

Given 2000 ---- 54 days

The provisions for 2000 men for 39 days can be completed by 'm' men for only 20 days.

i.e, 2000 ----- 39 days == m ---- 20 days

=> m x 20 = 2000 x 39

m = 3900

So total men for 20 days is 3900

=> 2000 old and 1900 new reinforcement.

Hence, reinforcement = 1900.

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Filed Under: Time and Work
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10 14459