Exams

In this type of question, we will first calculate the distance covered in given time.

Distance covered will be : Number of revolutions x Circumference 

So we will be having distance and time, from which we can calculate the speed. 

Radius of wheel = 70 / 2 = 35 cm

Distance covered in 40 revolutions will be 40*circumferene=40*2πr=40*2*227*35=8800cm = 88 m

Distance covered in 1 sec  = 8810=8.8m/s=8.8*185km/hr=31.68km/hr

No. of  sweets each student get = 20% of 65 = 13

No. of sweets each teacher get = 40% of 65 = 26

No. of sweets distributed to 65 students =  13 × 65 = 845

No. of sweets distributed to 4 teachers = 4 × 26 = 104

Therefore, the total no. of sweets there = 845 + 104 = 949.

Let the side of the square plot be 'a' ft.
Given area of the plot (a x a) = 289 => a = 17
Length of the fence = Perimeter of the plot = 4a = 68 ft.
Cost of building the fence = 68 x 58 = Rs. 3944.

The Feroz Shah Kotla Ground is a cricket ground built in 1883 in New Delhi is the second oldest international cricket stadium still functional in India, after the Eden Gardens in Kolkata. It also holds the record of the smallest cricket stadium in the world by boundary.