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Certification Questions

What are certifications?

Certification is the recognition of an individual to be qualified for a job or task. These Certification programs setup IT standards and play major role in developing a qualified workforce. Certifications can raise the technical standards.

Why certifications?

One can measure his/her abilities in their respective professional knowledge and present themselves through certificates. The certification programs assure technical proficiency of IT professionals by measuring their technical skills and knowledge in a specific IT support function or technology.

Who can do certifications?

Definitely who aim for professional growth in their respective functionality or technology can plan for Certifications. This can also tell how valuable certifications are to be potential employers. Any qualified and well experienced IT professional can step-up to take the certification.

How to do certifications?

When you decided to take the certification, well done! You have stepped up the professional ladder to upgrade your skills and knowledge. You can easily plan, work hard and grab a certification. Find some help from following steps.

  • Decide your certification – explore your skills and find a certification that matches your skill set.
  • Research the certification-evaluate the process of certification. Find details of validity, qualification for certification.
  • Evaluate your experience - asses your real experience with the material you gathered for certification and come up with a plan which areas to concentrate more.
  • Apply for certification – Get registered for your Exam.
  • Plan of study – you can study your well experienced areas yourself and can take trainings if required to boost your preparation. You can practice more through mock tests you find online, can keep discussing in forums and blogs.
  • Grab Certificate – finally, you can grab a certification with your positive attitude, hard work.
Popular Latest Rated
Q:

In the following pieces of code, B and D will compile without any error. True or false ?

A: StringBuffer sb1 = "abcd";

B: Boolean b = new Boolean("abcd");

C: byte b = 255;

D: int x = 0x1234;

E: float fl = 1.2;

A) TRUE B) FALSE
Answer & Explanation Answer: A) TRUE

Explanation:

The code segments B and D will compile without any error. A is not a valid way to construct a StringBuffer, you need to create a StringBuffer object using "new". B is a valid construction of a Boolean (any string other than "true" or "false" to the Boolean constructor will result in a Boolean with a value of "false"). C will fail to compile because the valid range for a byte is -128 to +127 (i.e., 8 bits, signed). D is correct, 0x1234 is the hexadecimal representation in java. E fails to compile because the compiler interprets 1.2 as a double being assigned to a float (down-casting), which is not valid. You either need an explicit cast, as in "(float)1.2" or "1.2f", to indicate a float.

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Subject: Oracle Certification
Job Role: Analyst , IT Trainer , Project Manager

7 7503
Q:

Which layer of the OSI model offers three different modes of communication : Simplex, half duplex, and full duplex?

A) Presentation B) Transport
C) Application D) Session
 
Answer & Explanation Answer: D) Session

Explanation:

The Session layer of the OSI model offers three different modes of communication : Simplex, half duplex, and full duplex.

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Filed Under: CCNA

1 7402
Q:

What protocol would you use if you were running xDSL and needed authentication?

Answer

PPPoE  or  PPPoA

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Subject: CCNA

5 7401
Q:

Which of the following descriptions about IPv6 is correct?

A) Addresses are not hierarchical and are assigned at random B) Broadcasts have been eliminated and replaced with multicasts
C) There are 2.7 billion addresses D) An interface can only be configured with one IPv6 address
 
Answer & Explanation Answer: B) Broadcasts have been eliminated and replaced with multicasts

Explanation:

There are no broadcasts with IPv6. Unicast , multicast, anycast, global, and link - local unicast are used.

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Filed Under: CCNA

1 7305
Q:

You have the following binary number :10110111. What are the decimal and hexadecimal equivalents?

A) 69/0x2102 B) 183/B7
C) 173/A6 D) 83/0xC5
 
Answer & Explanation Answer: B) 183/B7

Explanation:

You must be able to take a binary number and convert it into both decimal and hexadecimal. To convert to decimal, just add up the 1s using their values. The values that are turned on with the binary number of 10110111 are 128+32+16+4+2+1=183. To get the hexadecimal equivalent, you need to break the eight binary digits into nibbles (4 bits), 1011 and 0111. By adding up these values, you get 11 and 7. In hexadecimal, 11 is B, so the answer is 0xB7.

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Filed Under: CCNA

1 7093
Q:

What is the subnetwork address for a host with the IP address 200.10.5.68/28?

A) 200.10.5.56 B) 200.10.5.32
C) 200.10.5.64 D) 200.10.5.0
 
Answer & Explanation Answer: C) 200.10.5.64

Explanation:

This is a pretty simple question. A/28 is 255.255.255.240, which means that our block size is 16 in the fourth octent. 0,16, 32, 48, 64, 80, etc. The host is in the 64 subnet.

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Filed Under: CCNA

1 7083
Q:

An administrator issues the command "ping 127.0.0.1" from the command line prompt on a PC host named PC1. If an ICMP reply is received, what does this confirm?

A. The PC host PC1 has connectivity with a local host
B. The PC host PC1 has connectivity with a Layer 3 device
C. The PC host PC1 has a default gateway correctly configured
D. The PC host PC1 has connectivity up to Layer 5 of the OSI model
E. The PC host PC1 has the TCP/IP protocol stack correctly installed

Answer

Answer : E

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Subject: CCNA

11 7083
Q:

A receiving host has failed to receive all of the segments that it should acknowledge. What can the host do to improve the reliability of this communication session?

A) Send a different source port number B) Restart the virtual circuit
C) Decrease the sequence number D) Decrease the window size
 
Answer & Explanation Answer: D) Decrease the window size

Explanation:

A receiving host can control the transmitter by using flow control ( TCP uses windowing by default). By decreasing the window size, the receiving host can slow down the transmitting host so the receiving host does  not overflow its buffers.

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Filed Under: CCNA

0 7071