Sawaal

 Arithmetical Reasoning Questions

Popular Latest Rated
Q:

Khushi bought the bangles of equal number of Rs. 34 per piece, Rs. 42 per piece and Rs. 6 per piece. She spends total Rs. 1722 on all types of bangles. How many bangles did she buy of each type  ?

A) 27 B) 13
C) 17 D) 21
 
Answer & Explanation Answer: D) 21

Explanation:

Let number of bangles kushi purchase of each type = x

From the given data,

34x + 42x + 6x = 1722

x = 1722/82 = 21.

Report Error

View Answer Report Error Discuss

Filed Under: Arithmetical Reasoning
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

17 3620
Q:

In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many men will be catered to with remaining meal ?

A) 40 B) 30
C) 50 D) 25
 
Answer & Explanation Answer: B) 30

Explanation:

Here given 120 men = 200 children

therefore 1 child = 3/5 of Man------ step I

Now given that the food was consumed by 150 children

From step I we get 150 children =90 Men ( 1 child = 3/5 Man ie , 150 X 3/5 = 90)
So the food is for (120-90) men = 30 Men

Report Error

View Answer Report Error Discuss

Filed Under: Arithmetical Reasoning
Exam Prep: Bank Exams , CAT , GATE
Job Role: Bank Clerk

4 3580
Q:

How many feet are in a meter?

A) 3.214 B) 3.28084
C) 3.2516 D) 3.21456
 
Answer & Explanation Answer: B) 3.28084

Explanation:

We know that, 

1 meter = 100 cms. 

=> 1 meter = 3.28084 feet.

Report Error

View Answer Report Error Discuss

Filed Under: Arithmetical Reasoning
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

14 3575
Q:

In a class there are certain no. of boys and girls. If 15 girls are absent then no. of boys will be twice that of girls. If 45 boys are absent then girls strength will be 5 times that of boys. Find number of boys actually present ?

A) 40 B) 50
C) 55 D) 35
 
Answer & Explanation Answer: B) 50

Explanation:

15 girls are absent => b = 2(g-15)...... eqn...(1)

45 boys are absent => g - 15 = 5(b-45).....eqn...(2)

=> g = 5(b-45) + 15

=> b = 2((5(b-45)+15)-15)

=> b = 2(5b - 225 + 15 - 15)

=> b = 2(5b-225)

=> b = 10b - 450

=> 9b = 450

=> b = 50

so from equation(2)

g - 15 = 5(b - 45)

=> g - 15 = 5(50-45)

=> g - 15 = 5(5)

=> g = 25 + 15

=> g = 40

Therefore, the number of boys = 50 and girls = 40

Report Error

View Answer Report Error Discuss

Filed Under: Arithmetical Reasoning
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

2 3537
Q:

A Child has 1200 five rupee coins. He wants to place them in such a way that the number of rows and the number of columns remains the same. What is the minimum number of coins that he needs more for this purpose?

A) 125 B) 96
C) 35 D) 25
 
Answer & Explanation Answer: D) 25

Explanation:

We know that, to be in the form that the number of rows and the number of columns to be equal the number should be a perfect square (a2).

Given number is 1200

The perfect number which is above and near to 1200 is 1225 which is 35  35.

Therefore, The minimum number of coins he need is 25. 

Report Error

View Answer Report Error Discuss

Filed Under: Arithmetical Reasoning
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Network Engineer , Bank PO , Bank Clerk

12 3513
Q:

An intelligent boy is doing a jigsaw with 275 pieces. Each day that he fits pieces together there are fewer pieces left, and it is reasonable to assume that he fits more pieces each day because the number left to sort out diminishes progressively. Hence he is able to fit an extra piece as each day goes by. On the first day he fits 20 pieces. How many days does it take for him to complete the puzzle ?

A) 11 days B) 15 days
C) 13 days D) 16 days
 
Answer & Explanation Answer: A) 11 days

Explanation:

Let 'n' number of days it take to complete.

 

we know that sum of n number= n/2[2a+(n-1)d]
where a=20,d=1;
n/2[2x20+(n-1)1]=275
n[n+39]=550
n2 + 39n - 550 = 0
 n2+ 50n - 11n - 550 = 0
(n-11) (n-50) = 0
n-11 = 0;
n = 11(Days).

Report Error

View Answer Report Error Discuss

Filed Under: Arithmetical Reasoning
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

2 3457
Q:

On sport’s day, if 12 children were made to stand in each column, 98 columns could be formed. After a certain music being played the plan was that the children have to stand in concentric circles such that the innermost circle will have one student, the next circle will have two students, the third circle will have 3 students and so on. How many circles will be formed in this manner ?

A) 44 B) 46
C) 48 D) 49
 
Answer & Explanation Answer: C) 48

Explanation:

No. of students will be 98 x 12 = 1176
let us consider n circles then 1 + 2 + 3 + ....+ n = 1176
n(n+1)/2 = 1176
n = 48 circles.

Report Error

View Answer Report Error Discuss

Filed Under: Arithmetical Reasoning
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

3 3453
Q:

What is the value of 28 tens?

A) 28 B) 2
C) 2800 D) 280
 
Answer & Explanation Answer: D) 280

Explanation:

Here asked for the value of 28 tens

=> 28 x 10 = 280.

Report Error

View Answer Report Error Discuss

Filed Under: Arithmetical Reasoning
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

2 3414