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Q:

Who of the following Portuguese is regarded as a 'monster in human disguise' and the one who had no bowels of compassion?

A) Vasco da Gama B) Albuquerque
C) Almeida D) Joao de Castro
 
Answer & Explanation Answer: A) Vasco da Gama

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Filed Under: Indian History

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Q:

Which of the following is the Trophy / Cups associated with the game of Hockey?

A) Derby B) Agha Khan Cup
C) Merdeka D) Vizzy Trophy
 
Answer & Explanation Answer: B) Agha Khan Cup

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Filed Under: Sports

22 6936
Q:

Rearrange the parts of the sentence in correct order.

In developing countries today

P : urban health conditions

Q : than rural health conditions

R : seem to be better

A) PRQ B) PQR
C) QRP D) RPQ
 
Answer & Explanation Answer: A) PRQ

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Exam Prep: Bank Exams

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Q:

Bhangra is the folk dance of which Indian state

Answer

Punjab

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Subject: Indian Culture

97 6933
Q:

Major coalfields of India are located in the river valley of

A) Damodar B) Godavari
C) Mahanadi D) Wardha
 
Answer & Explanation Answer: A) Damodar

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Filed Under: Indian Economy

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Q:

5 L from A are V?

Answer

5 L from A are V --- 5 Letters from Alphabets are Vowels.


 

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Subject: Logic Puzzles Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: IT Trainer , Database Administration , Bank PO , Bank Clerk , Analyst

13 6926
Q:

Select the word with the correct spelling.

 

A) oxidieser B) thespian
C) aproval D) secreetes
 
Answer & Explanation Answer: B) thespian

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Exam Prep: Bank Exams

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Q:

The oxidation number of Cr in K2Cr2O7 is

A) +6 B) -5
C) +3 D) -4
 
Answer & Explanation Answer: A) +6

Explanation:

We will rewrite the formula as an equation.

2K + 2Cr + 7O = 0

The zero comes from there being no overall charge on the compound.

Each oxidation number is represented by the element's symbol.

Since this compound is not a peroxide or superoxide, the oxidation value for O is -2

K being in group 1 has a +1 charge and therefore has an oxidation number of K is +1

Now, by putting known values in we have:

2(+1) + 2(Cr) + 7(-2) = 0

2 + 2Cr -14 = 0

2Cr = +12

Cr = +6.

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Filed Under: Chemistry
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