Q:
What would be the output of the following program?
main()
{
extern int fun ( float );
int a;
a = fun ( 3. 14 );
printf ("%d", a);
}
int fun ( aa )
float aa ;
{
return ( (int) aa );
}
Answer
Error occurs because we have mixed the ANSI prototype with K & R style of function definition.
When we use ANSI prototype for a function and pass a float to the function it is promoted to a double. When the function accepts this double into a float a type mismatch occurs hence the error.
The remedy for this error could be to define the function as :
int fun (float aa)
{
....
}
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