255+ Data Interpretation Questions and Answers With Explanation

Q:

Read the following data and answer the question.

What is the average number of children per house?

A) 1.34	B) 1.59
C) 1.84	D) 1.09

Answer & Explanation Answer: A) 1.34

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Q:

Refer the data and answer the question.

If the company has issued 6 lakh shares between its five partners and if Chinmay offers to sell 15000 of his shares to Ejaz, then Ejaz will have how many shares?

A) 300000 shares	B) 270000 shares
C) 285000 shares	D) 255000 shares

Answer & Explanation Answer: C) 285000 shares

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Q:

Refer the below table and answer the question.

Between 10pm to 6am, a fitness band records the data. How long was the user in light sleep or was in Extremely light sleep?

A) 0.7 hours	B) 1.2 hours
C) 1.7 hours	D) 2.3 hours

Answer & Explanation Answer: B) 1.2 hours

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Q:

Refer the below data table and answer the following question.

For which of the following pairs of years the total exports from the three companies together are equal?

A) 2011 & 2013	B) 2013 & 2014
C) 2011 & 2012	D) 2014 & 2015

Answer & Explanation Answer: B) 2013 & 2014

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Q:

Refer the below table and answer the following question.

If 400 calories are burned by jogging 5 km, then how many calories were burnt in the given week?

A) 1890 calories	B) 1840 calories
C) 1790 calories	D) 1740 calories

Answer & Explanation Answer: B) 1840 calories

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Q:

Refer the below data and answer the following question.

What was the increase in the height of the child from 10th Birthday to 15th birthday?

A) 50 cm	B) 45 cm
C) 40 cm	D) 35 cm

Answer & Explanation Answer: C) 40 cm

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Q:

If the total number of bikes sold in 2009 was 6000, then according to the given data, bikes of which colours were sold equally?

A) Brown and black put together and green	B) Yellow and green put together and golden
C) Blue and green put together and golden	D) Silver and green put together and golden

Answer & Explanation Answer: A) Brown and black put together and green

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Q:

The following table shows the number of new employees added to different categories of employees in a company and also the number of employees from these categories who left the company every year

1.What is the difference between the total number of Technicians added to the Company and the total number of Accountants added to the Company during the years 1996 to 2000?

A. 128 B. 112 C. 96 D. 88

2. What was the total number of Peons working in the Company in the year 1999?

A. 1312 B. 1192 C. 1088 D. 968

3. For which of the following categories the percentage increase in the number of employees working in the Company from 1995 to 2000 was the maximum?

A. Managers B. Technicians C. Operators D. Accountants

4. What is the pooled average of the total number of employees of all categories in the year 1997?

A. 1325 B. 1195 C. 1265 D. 1235

5. During the period between 1995 and 2000, the total number of Operators who left the Company is what percent of total number of Operators who joined the Company?

A. 19% B. 21% C. 27% D. 29%

Answer

1. ANSWER : D

Explanation - Required difference

= (272 + 240 + 236 + 256 + 288) - (200 + 224 + 248 + 272 + 260)

= 88.

2. ANSWER : B

Explanation - Total number of Peons working in the Company in 1999

= (820 + 184 + 152 + 196 + 224) - (96 + 88 + 80 + 120)

= 1192.

3. ANSWER : A

Explanation - Number of Managers working in the Company:

In 1995 = 760.
In 2000 = (760 + 280 + 179 + 148 + 160 + 193) - (120 + 92 + 88 + 72 + 96)= 1252.

Therefore, Percentage increase in the number of Managers

= $\frac{(1252 - 760)}{760} \times 100$ %= 64.74%

Number of Technicians working in the Company:
In 1995 = 1200.
In 2000 = (1200 + 272 + 240 + 236 + 256 + 288) - (120 + 128 + 96 + 100 +112) = 1936.

Therefore, Percentage increase in the number of Technicians

= $\frac{(1936 - 1200)}{1200} \times 100$ % = 61.33%

Number of Operators working in the Company:

In 1995 = 880.
In 2000 = (880 + 256 + 240 + 208 + 192 + 248) - (104 + 120 + 100 + 112 + 144) = 1444.

Therefore, Percentage increase in the number of Operators

= $\frac{(1444 - 880)}{880} \times 100$ % = 64.09%

Number of Accountants working in the Company:

In 1995 = 1160.
In 2000 = (1160 + 200 + 224 + 248 + 272 + 260) - (100 + 104 + 96 + 88 + 92) = 1884.

Therefore, Percentage increase in the number of Accountants

= $\frac{(1884 - 1160)}{1160} \times 100$ % = 62.14%

Number of Peons working in the Company:

In 1995 = 820.
In 2000 = (820 + 184 + 152 + 196 + 224 + 200) - (96 + 88 + 80 + 120 + 104) = 1288.

Therefore, Percentage increase in the number of Peons

= $\frac{(1288 - 820)}{820} \times 100$ % = 57.07%

Clearly, the percentage increase is maximum in case of Managers.

4. ANSWER : B

Explanation - Total number of employees of various categories working in the Company in 1997 are:

Managers = (760 + 280 + 179) - (120 + 92) = 1007.

Technicians = (1200 + 272 + 240) - (120 + 128) = 1464.

Operators = (880 + 256 + 240) - (104 + 120) = 1152.

Accountants = (1160 + 200 + 224) - (100 + 104) = 1380.

Peons = (820 + 184 + 152) - (96 + 88) = 972.

Therefore, Pooled average of all the five categories of employees working in the Company in 1997 = 1/5 x (1007 + 1464 + 1152 + 1380 + 972)

= 1/5 x (5975)

= 1195.

5. ANSWER : D

Explanation - Total number of Operators who left the Company during 1995 - 2000

= (104 + 120 + 100 + 112 + 144)

= 580.

Total number of Operators who joined the Company during 1995 - 2000

= (880 + 256 + 240 + 208 + 192 + 248

= 2024.

Therefore, Required Percentage

= (580/2024)x100% = 28.66% ~= 29%.

Quantitative Aptitude - Data Interpretation Questions

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