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 Volume and Surface Area Questions

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FACTS  AND  FORMULAE  FOR  VOLUME  AND  SURFACE  AREA  QUESTIONS

 

 

I. CUBOID

   Let length=l, breadth =b and height =h units. Then,

1. Volume = (l x b x h)

2. Surface area = 2(lb +bh + lh) sq.units

3. Diagonal =l2+b2+h2 units

 

 

II. CUBE 

Let each edge of a cube be of length a. Then,

1. Volume = a3 cubic units.

2. Surface area = 6a2 sq.units

3. Diagonal = 3a units

 

 

III. CYLINDER 

Let radius of base = r and Height (or Length) = h. Then, 

1.Volume = πr2h cubic units 

2. Curved surface area = 2πrh sq.units

3. Total surface area = 2πrh+2πr2 sq.units

 

 

IV. CONE 

Let radius of base =r and Height = h. Then, 

1. Slant height, l=h2+r2 units

 

2. Volume = 13πr2h cubic units.

 

3. Curved surface area = πrlsq.units 

 

4. Total surface area = πrl+πr2sq.units

 

 

V. SPHERE 

Let the radius of the sphere be r. Then, 

1. Volume =43πr3 cubic units

2. Surface area = 4πr2 sq.units

 

 

VI. HEMISPHERE 

Let the radius of a hemisphere be r. Then, 

1. Volume = 23πr3 cubic units.

2. Curved surface area = 2πr2 sq.units

3. Total surface area = 3πr2 sq.units

 

Q:

What is the ratio between the volumes of a cylinder and cone of the same height and of the same diameter

A) 2:1 B) 3:1
C) 4:1 D) 5:1
 
Answer & Explanation Answer: B) 3:1

Explanation:

Volume of cylinder / Volume of cone = 3/1

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1 7614
Q:

A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8m, the volume of the box (in m3) is:

A) 4830 B) 5120
C) 6420 D) 8960
 
Answer & Explanation Answer: B) 5120

Explanation:

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4 7380
Q:

Find the ratio of the surfaces of the inscribed and circumscribed spheres about a cube.

A) 1:2 B) 1;3
C) 1:4 D) 1:5
 
Answer & Explanation Answer: A) 1:2

Explanation:

 4×3.14×r2 : 4×3.14×r2 = 1 : 2  

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10 7296
Q:

What part of the volume of a cube is the pyramid whose base is the base of then cube and whose vertex is the center of the cube?

A) 4:1 B) 5:1
C) 6:1 D) 7:1
 
Answer & Explanation Answer: C) 6:1

Explanation:

Volume of the cube/volume of pyramid=a313a2×a2

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1 7112
Q:

If the radius of base and height of a cone are increased by 10%, find the percentage of increase of its volume

A) 33.5% B) 33.1%
C) 32.1% D) 53.1%
 
Answer & Explanation Answer: B) 33.1%

Explanation:

v1= 13πr12h1

 

v2=13πr22h2

 

% Increase in volume = (V2-V1) / (V2*100)

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9 7001
Q:

A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

A) 2.91 m B) 3 m
C) 5.82 m D) None of these
 
Answer & Explanation Answer: B) 3 m

Explanation:

Area of the park = (60 x 40) = 2400 sq.m  

Area of the lawn = 2109  sq.m 

Area of the crossroads = (2400 - 2109) = 291 sq.m   

 

Let the width of the road be x metres. Then,   

60x + 40x - (x * x) = 291  

=>(x * x) - 100x + 291 = 0    

=>(x - 97)(x - 3) = 0  

=>x=3

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1 6988
Q:

A single pipe of diameter x has to be replaced by six pipes of diameters 12 cm each. The pipes are used to covey some liquid in a laboratory. If the speed/flow of the liquid is maintained the same then the value of x is ?

A) 14.69 cm B) 29.39 cm
C) 18.65 cm D) 22.21 cm
 
Answer & Explanation Answer: B) 29.39 cm

Explanation:

Volume of water flowing through 1 pipe of diameter x = Volume discharged by 6 pipes of diameter 12 cms.

 

As speed is same, area of cross sections should be same. 

 

Area of bigger pipe of diameter x = Total area of 6 smaller pipes of diameter 12 

i.e πR2 = 6πR12   

Here R = R and R1 = 12/2 = 6   

⇒R2 = 6×6×6   

R = 14.696   

=> D = X = 14.696 * 2 = 29.3938 cm.

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9 6689
Q:

Find the area of a square, one of whose diagonals is 3.8 m long.

A) 4.22 sq.m B) 5.22 sq.m
C) 6.22 sq.m D) 7.22 sq.m
 
Answer & Explanation Answer: D) 7.22 sq.m

Explanation:

Area of the square = 12×diagonal2=  1/2 * 3.8 * 3.8 = 7.22 sq.m

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