Time and Work Questions

FACTS  AND  FORMULAE  FOR  TIME  AND  WORK  QUESTIONS

 

 

1. If A can do a piece of work in n days, then A's 1 day's work =1n

2. If A’s 1 day's work =1n, then A can finish the work in n days.

 

3. A is thrice as good a workman as B, then:

Ratio of work done by A and B = 3 : 1.

Ratio of times taken by A and B to finish a work = 1 : 3.

 

NOTE : 

Efficiency1No of time units

 

 Efficiency × Time = Constant Work

 

Hence, Required time = WorkEfficiency

 

Whole work is always considered as 1, in terms of fraction and 100% , in terms of percentage.

In general, number of day's or hours = 100Efficiency

Q:

Aadi can do a piece of work in 12 days alone, Bunny can do the same work in 16 days alone. After Aadi has been working for 5 days and Bunny for 7 days, Charan finishes it in 14 days. In how many days will Charan alone be able to do the work?

A) 96 days B) 48 days
C) 24 days D) 12 days
 
Answer & Explanation Answer: A) 96 days

Explanation:

Let number of days Charan can do the same work alone is 'd' days.

According to the given data,

512 + 716 + 14d = 114d = 1 - 20 + 214814d = 48 - 4148d = 14 x 487d = 96 days

 

Therefore, Charan alone can complete the work in 96 days.

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Q:

A,B,C can complete a work in 15,20 and 30 respectively.They all work together for two days then A leave the work,B and C work some days and B leaves 2 days before completion of that work.how many days required to complete the whole work?

Answer

Given A,B,C can complete a work in 15,20 and 30 respectively.


The total work is given by the LCM of 15, 20, 30 i.e, 60.


A's 1 day work = 60/15 = 4 units


B's 1 day work = 60/20 = 3 units


C's 1 day work = 60/30 = 2 units


(A + B + C) worked for 2 days = (4 + 3 + 2) 2 = 18 units


 Let B + C worked for x days = (3 + 2) x = 5x units


C worked for 2 days = 2 x 2 = 4 units


Then, 18 + 5x + 4 = 60


22 + 5x = 60


5x = 38


x = 7.6


 


Therefore, total number of days taken to complete the work = 2 + 7.6 + 2 = 11.6 = 11 3/5 days.

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Q:

In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ?

A) 145 B) 165
C) 175 D) 135
 
Answer & Explanation Answer: C) 175

Explanation:

Given that,

 working days = 5

 working hours = 8

 A man get rupess per hour is Rs.2.40

 So in one day the man get total rupees is 2.40 x 8 = 19.2

 So in 5 days week the man get total rupees is 19.2 x 5 = 96

 So in 4 week the man get total rupees is 96 x 4 = 384

 So the man worked for = 160hours in 4 weeks

 

 But given that the man earned Rs.432

 

 Hence remaning money is (432-384 = 48)which is earn by doing overtime work

 


Overtime hours  = 48/3.20 = 15


So total worked hours is = 15 + 160 = 175.

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Q:

9 girls working 7 hours a day can complete a piece of work in 15 day. In how many days can 6 girls working for 9 hours a day, complete the same piece of work?

A) 35/4 days B) 17.5 days
C) 19 3/4 days D) 37/3 days
 
Answer & Explanation Answer: B) 17.5 days

Explanation:

Let the number of days be 'p' 

As the work is same, we know that

M1 x D1 x H1 = M2 x D2 x H2

Where M = Men, D = Days, H = Hours per day 

Here M1 = 9, D1 = 15, H1 = 7 

M2 = 6, D2 = p, H2 = 9 

=> 9 x 15 x 7 = 6 x p x 9 

=> p = 35/2 = 17.5 days.

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Q:

A can do a piece of work in 15 days and B can do it in 16 days and C can do it 24 days. They started the work together and A leaves after 3 days and B leaves after 4 days from the beginning. How long will work lost ?

A) 10 2/3 days B) 13 1/5 days
C) 12 2/3 days D) 11 5/7 days
 
Answer & Explanation Answer: B) 13 1/5 days

Explanation:

3/15 + 4/16 + x/24 = 1

x=1315

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Q:

A can complete a piece of work in 12 days and B is 60% more efficient than A. In how many days B will complete the same work  ?

A) 8.7 hrs B) 5.2 hrs
C) 5 hrs D) 7.5 hrs
 
Answer & Explanation Answer: D) 7.5 hrs

Explanation:

Ratio of times taken by A and B = 160 : 100
A can do the work in 12 days
Let B can do the work in "D" days
=> 160:100 = 12 : D
=> D = 12 x 100/160 = 7.5 hrs

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Q:

M can complete a piece of work in 10 days. N is 33.33% less efficient than M. calculate the number of days required to both to complete the work?

A) 6 days B) 8 days
C) 11 days D) 13 days
 
Answer & Explanation Answer: A) 6 days

Explanation:

M = 10 days

The ratio of efficiency of M & N are 3 : 2

Hence, the time rquired for N alone = 15 days

=> Required time taken t=by both to complete the work = M x N / M + N 

= 10 x 15/ 10 + 15

= 150/25

= 6 days.

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Q:

Lasya alone can do a work in 16 days. Srimukhi’s efficiency is 20 % lesser than that of Laya. If Rashmi and Srimukhi together can do the same work in 12 days, then find the efficiency ratio of Rashmi to that of Lasya?

A) 19 : 7 B) 30 : 19
C) 8 : 15 D) 31 : 17
 
Answer & Explanation Answer: C) 8 : 15

Explanation:

Given Lasya can do a work in 16 days.

 

Now, time taken by Srimukhi alone to complete the work = 16 x 100/80

 

Time taken by Rashmi = n days

 

=> (12 x 20)/(20 - 12) = (12 x 20)/n

 

=> n= 30 days.

 

Required ratio of efficiencies of Rashmi and Lasya = 1/30  ::  1/16  = 8 : 15.

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