320+ Time and Distance Problems With Solutions And Explanation

Q:

A person travels from K to L a speed of 50 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips ?

A) 55 kmph	B) 58 kmph
C) 60 kmph	D) 66 kmph

Answer & Explanation Answer: C) 60 kmph

Explanation:

Speed on return trip = 150% of 50 = 75 km/hr.

Average speed = (2 x 50 x 75)/(50 + 75) = 60 km/hr.

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Q:

The respective ratio between the speed of a bike, a van and lorry is 3 : 5 : 2. The speed of the van is 250 percent of the speed of the lorry which covers 360 km in 12 hours. What is the average speed of the bike and the van together?

A) 60 kmph	B) 62 kmph
C) 64 kmph	D) 63 kmph

Answer & Explanation Answer: A) 60 kmph

Explanation:

Speed of lorry = $\frac{360}{12}$ = 30 kmph

Speed of van = $\frac{250}{100} x 30$ = 75 kmph

Speed of bike = $\frac{3}{5} x 75$ = 45 kmph

Therefore, now required average speed of bike and van = $\frac{75 + 45}{2}$ = 60 kmph.

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Q:

K is 50% faster than L. If L starts at 9 A.M. and K starts at 10 A.M. L travels at a speed of 50 km/hr. If L and K are 300 kms apart, The time when they meet when they travel in opposite direction is ?

A) 12 pm	B) 1 pm
C) 11 am	D) 11:30 am

Answer & Explanation Answer: A) 12 pm

Explanation:

let 't' be the time after which they met since L starts.

Given K is 50% faster than L

50 t + 1.5*50(t-1) = 300

50 t +75 t = 300 + 75

t = 375 / 125 = 3 hrs past the time that L starts

So they meet at (9 + 3)hrs = 12:00 noon.

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Q:

Two trains are running with speeds 30 kmph and 58 kmph respectively in the same direction. A man in the slower train passes the faster train in 18 seconds. Find the length of the faster train?

A) 105 mts	B) 115 mts
C) 120 mts	D) 140 mts

Answer & Explanation Answer: D) 140 mts

Explanation:

Speeds of two trains = 30 kmph and 58 kmph

=> Relative speed = 58 - 30 = 28 kmph = 28 x 5/18 m/s = 70/9 m/s

Given a man takes time to cross length of faster train = 18 sec

Now, required Length of faster train = speed x time = 70/9 x 18 = 140 mts.

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Q:

Two trains start from same place at same time at right angles to each other. Their speeds are 36km/hr and 48km/hr respectively. After 30 seconds the distance between them will be ?

A) 900 mts	B) 300 mts
C) 250 mts	D) 500 mts

Answer & Explanation Answer: D) 500 mts

Explanation:

Using pythagarous theorem,
distance travelled by first train = 36x5/18x30 = 300m
distance travelled by second train = 48x5/18x30 = 400m
so distance between them =√( 90000 + 160000) = √250000 = 500mts.

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Q:

In what time a 360 m. long train moving at the speed of 44 km/hr will cross a 140 m. long bridge ?

A) 36 sec	B) 39 sec
C) 41 sec	D) 43 sec

Answer & Explanation Answer: C) 41 sec

Explanation:

Speed = 44 kmph x 5/18 = 110/9 m/s

We know that, Time = distance/speed

Time = (360 + 140) / (110/9)

= 500 x 9/110 = 41 sec.

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Q:

Den Bosch and Eastbourne are two famous cities 300 km apart. Maradona starts from Den Bosch at 8:24 am . An hour later pele starts from Den Bosch. After travelling for 1 hour , Pele reaches Nottingham that Maradona had passed 40 minutes earlier. Nottingham falls on the way from Den Bosch to Eastbourne. If pele and Maradona just reaches Eastbourne at the same time, what are thespeeds of the Maradona and Pele Respectively?

A) 100 km/h , 125 km/h	B) 60 km/h , 80 km/h
C) 60 km/h , 75 km/h	D) 75 km/h , 100 km/h

Answer & Explanation Answer: D) 75 km/h , 100 km/h

Explanation:

Let Pele x km in 1 hour. so Maradona takes (2h-40min)=1 h 20 min to cover x km. Let speed of Maradona and Pele be M and P respectively than

x =M x (4/3) and x= P x 1

=> M/P = 3/4

Again $\frac{300}{M} = \frac{300}{P} = 1$

$\Rightarrow \frac{300}{3 k} - \frac{300}{4 k} = 1$

=> k= 25

M= 3k = 75 km/h and P= 4k = 100 km/h

( Through options it is very easy to solve)

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Q:

Two stations A and B are 200 km apart on a straight track. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?

A) 12 a.m.	B) 1 p.m.
C) 11 a.m.	D) 12 p.m.

Answer & Explanation Answer: D) 12 p.m.

Explanation:

Assume both trains meet after 'p' hours after 7 a.m.
Distance covered by train starting from A in 'p' hours = 20p km
Distance covered by train starting from B in (p-1) hours = 25(p-1)
Total distance = 200
=> 20x + 25(x-1) = 200
=> 45x = 225
=> p= 5
Means, they meet after 5 hours after 7 am, ie, they meet at 12 p.m.

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