Q:
P, Q and R start simultaneously from A to B. P reaches B, turns back and meet Q at a distance of 11 km from B. Q reached B, turns back and meet R at a distance of 9 km from B. If the ratio of the speeds of P and R is 3:2, what is the distance between A and B ?
Answer & Explanation
Answer: A) 99
Explanation: Let, Distance between A and B = d
Distance travelled by P while it meets Q = d + 11
Distance travelled by Q while it meets P = d – 11
Distance travelled by Q while it meets R = d + 9
Distance travelled by R while it meets Q = d – 9
Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11
The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9
But given Ratio of speeds of P & R => P : R = 3 : 2
=> = 3/2
=> d = 1, 99
=> d = 99 satisfies.
Therefore, Distance between A and B = 99
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