Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

What is the value of sin6θ + cos6θ + 3 sin2θ cos2θ 1?

A) 0 B) 1
C) 2 D) 4
 
Answer & Explanation Answer: A) 0

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Q:

What is the value of cosec -7π/6?

A) -2 B) 2
C) 2/√3 D) -2/√3
 
Answer & Explanation Answer: B) 2

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Q:

If cos ­-11π/6 = x, then the value of x is

A) -√3/2 B) 1/2
C) -2 D) √3/2
 
Answer & Explanation Answer: D) √3/2

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Q:

If a+b+c = 0, then (a^3 + b^3 + c^3)^2 = ?

A) 27abc B) 9abc
C) 3abc D) 9a^2b^2c^2
 
Answer & Explanation Answer: D) 9a^2b^2c^2

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Q:

If πsinθ= 1, πcosθ= 1, then (3tan 23θ+1) is

A) 1 B) √3
C) 2 D) 1/√3
 
Answer & Explanation Answer: C) 2

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Q:

If x = 999, y = 1000, z = 1001, then the value of x3+y3+z3-3xyzx-y+z is

A) 1000 B) 9000
C) 1 D) 9
 
Answer & Explanation Answer: D) 9

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Q:

If a - b = 2 and ab = 24, then what is the value of a3- b3?

A) 280 B) 124
C) 140 D) 152
 
Answer & Explanation Answer: D) 152

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Q:

In the question given below, two equations are provided. Solve the equations and establish the relationship between x and y

I. 2x2-13x-189=0 II. 2y2-3y-189=0

A) x>y B)  x≥y
C)  x<y D) x≤y
 
Answer & Explanation Answer:

Explanation:

I. 2x2 - 13x - 189 = 0 2x2 - 27x + 14x - 189 = 0 x(2x - 27) + 7(2x - 27) = 0 x = -7, 27/2

II. 2y2 - 3y - 189 = 0 2y2 - 21y + 18y - 189 = 0 y(2y - 21) + 9(2y - 21) = 0 y = -9, 21/2

When x, as well as y, have both positive and negative values then no relationship can be established between them because if we consider x to be positive then the negative value of y will be lesser than x. If we consider x to be negative then positive value of y will be greater than x.

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