Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

Solve the following : -1/4 { -45 - (-96) / (-32)} = ?

A) 12 B) 10.5
C) -12 D) -10.5
 
Answer & Explanation Answer: A) 12

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5 2038
Q:

If Tan θ = 7/24, then what is the value of Sec θ?

A) 24/25 B) 24/7
C) 25/7 D) 25/24
 
Answer & Explanation Answer: D) 25/24

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9 2037
Q:

(secA ­- tanA)/(cosecA + cotA) is equal to

A) (secA -­ cotA) / (cosecA + tanA) B) (secA -­ cosA) / (cosecA + sinA)
C) (cosecA -­ cotA) / (secA + tanA) D) (secA + cosA) / (cosecA -­ sinA)
 
Answer & Explanation Answer: C) (cosecA -­ cotA) / (secA + tanA)

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0 2034
Q:

If (x + 1/x) = 3, then x8+1x8 is equal to

A) 2201 B) 2203
C) 2207 D) 2213
 
Answer & Explanation Answer: C) 2207

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7 2028
Q:

If cosC + cosD = x, then value of x is

A) 2cos[(C+D)/2]cos[(C-D)/2] B) 2sin[(C+D)/2]sin[(C-D)/2]
C) 2cos[(C+D)/2]sin[(C-D)/2] D) 2sin[(C+D)/2]cos[(C-D)/2]
 
Answer & Explanation Answer: A) 2cos[(C+D)/2]cos[(C-D)/2]

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0 2021
Q:

If 1 + (1/2) + (1/3) + ... + (1/20) = k, then what is the value of (1/4) + (1/6) + (1/8) + ... + (1/40)?

A) k/2 B) 2k
C) (k – 1)/2 D) (k + 1)/2
 
Answer & Explanation Answer: C) (k – 1)/2

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11 2017
Q:

If secA - tanA = x, then the value of x is

A) 1/(sec2A - tan2A) B) 1/(sec2A + tan2A)
C) 1/√[(sec2A - tan2A)] D) 1/(secA + tanA)
 
Answer & Explanation Answer: D) 1/(secA + tanA)

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1 2007
Q:

What is the value of 3.6×1.62+0.48×3.61.8×0.8+10.8×0.3-2.16 ?

A) 2.4 B) 2
C) 4 D) 3
 
Answer & Explanation Answer: D) 3

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1 2005