Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

Simplify (533bxaz)/(41ab)

A) 17xzb B) 19xz
C) 13xz D) 31ab
 
Answer & Explanation Answer: C) 13xz

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Q:

p3 + q3 + r3  3pqr = 4. If a = q + r, b = r + p and c = p + q, then what is the value of a3 + b3 + c3  3abc?

A) 4 B) 8
C) 2 D) 12
 
Answer & Explanation Answer: B) 8

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Q:

x, y and z are real numbers. If x3 + y3 + z3 = 13, x + y + z = 1 and xyz = 1, then what is the value of xy + yz + zx?

A) -1 B) 1
C) 3 D) -3
 
Answer & Explanation Answer: D) -3

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Q:

For which value of ‘g’ the linear graph of 6x + 12y +9 = 0 and 2x + gy + 3 = 0 has infinite number of solutions?

A) 3 B) 4
C) 6 D) 9
 
Answer & Explanation Answer: B) 4

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Q:

If 4(x + 1) - 3 < 3 - x < 2x + 5; then the value of x is

A) -1 B) 0
C) -2 D) 3
 
Answer & Explanation Answer: B) 0

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Q:

If a -­ b = 6 and ab =16, then a3 -­ b3 is

A) 504 B) 702
C) 728 D) 511
 
Answer & Explanation Answer: A) 504

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Q:

What are the co-ordinates of the centroid of a triangle, whose vertices are A(1, -5), B(-4, 0) and C(3, -4)?

A) ( 0, 3) B) ( 0, -3)
C) ( 0, -5) D) ( 0, 5)
 
Answer & Explanation Answer: B) ( 0, -3)

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Q:

If sec2A cosec2A = x, then x is

A) sec2A + cosec2A + 2 B) tan2A + cot2A - 2
C) tan2A + cot2A + 2 D) sec2A + cosec2A - 2
 
Answer & Explanation Answer: C) tan2A + cot2A + 2

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