Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

Calculate the value of 0.77777 + 0.7777 + 0.777 + 0.77 + 0.7 + 0.07.

A) 3.86274 B) 3.80247
C) 3.85274 D) 3.87247
 
Answer & Explanation Answer: D) 3.87247

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Q:

P(4,2) and R(-2,0) are vertices of a rhombus PQRS. What is the equation of diagonal QS.

A) x - 3y = -2 B) 3x + y = 4
C) 3x + y = -4 D) x - 3y = 2
 
Answer & Explanation Answer: B) 3x + y = 4

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Q:

If the expression px3  qx2  7x  6 is completely divisible by x2  x  6, then what is the value of p and q respectively?

A) 0, 1 B) 1, 0
C) 2, 1 D) 1, 2
 
Answer & Explanation Answer: B) 1, 0

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Q:

Sum of twice a fraction and its reciprocal is 17/6. What is the fraction?

A) 4/3 B) 5/4
C) 3/4 D) 4/5
 
Answer & Explanation Answer: C) 3/4

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Q:

A spherical lead ball of radius 6 cm is melted and small lead balls of radius 3 mm are made. The total number of possible small lead balls is

A) 4250 B) 4000
C) 8005 D) 8000
 
Answer & Explanation Answer: D) 8000

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Q:

What is the value of tan4A + tan2A?

A) sec4A - sec2A B) sec4A + sec2A
C) cosec4A - sec2A D) sec4A + cosec2A
 
Answer & Explanation Answer: A) sec4A - sec2A

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Q:

Sum of cubes of first n even natural numbers.

Answer

Proof of Sum of cubes of first n even natural numbers ::


sum_of_cubes_of_first_n_even_natural_numbers1556603651.png image


 


Hence, in other words, the sum of the first n cubes is the square of the sum of the first n natural numbers.

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Q:

On dividing 256a2b2c2 by 64a2, we get

A) 2cxc B) 2bxb
C) 4 bxb.cxc D) 4
 
Answer & Explanation Answer: C) 4 bxb.cxc

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