Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

If sin x + cos x = √2 sin x, then the value of tan x is

A) √2 - 1 B) √2 + 1
C) 1 D) √2
 
Answer & Explanation Answer: B) √2 + 1

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Q:

The value of cos0 deg is

A) 0 B) infinite
C) not defined D) 1
 
Answer & Explanation Answer: D) 1

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Q:

How many solutions does a pair of linear equations will have, if the equations are 4x+5y-6=0 and 16x+20y+20=0?

 

A) 0 B) 1
C) 2 D) Infinite
 
Answer & Explanation Answer: A) 0

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Q:

Factors of  x2 + 7x + 10 are

A) (x-5)(x-2) B) (x+5)(x+2)
C) (x-5)(x+2) D) (x-4)(x+2)
 
Answer & Explanation Answer: B) (x+5)(x+2)

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Q:

The expenses of a person increase by Rs. 50000 for every month in February and March. If his expenses in January was Rs. 50000, calculate his average expenditure (in Rs.) from January to March.

A) 100000 B) 150000
C) 75000 D) 50000
 
Answer & Explanation Answer: A) 100000

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Q:

10 dozen apples, 15 dozen mangoes & 20 dozen oranges are kept for sale. 1/2, 1/3rd & 1/4th of each item respectively have been added. What is the total number of fruits kept for sale now?

A) 720 B) 600
C) 580 D) 820
 
Answer & Explanation Answer: A) 720

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Q:

Two circles of equal radii intersect each other such that one circle will pass through the centre of the other circle. The distance between the centre of two circles is equal to 6 cm. Find the length (in cm) of common chord.

 

A) √3   B) 2√3
C) 3√3 D) 6√3
 
Answer & Explanation Answer: D) 6√3

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Q:

The value of (0.00000729/0.00000027) is

A) 0.27 B) 0.027
C) 2.7 D) 27
 
Answer & Explanation Answer: D) 27

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